Why are d and f orbital electrons poor shielders of nuclear charge ?

Answer 1

This is classified interaction. The realist must know that
shields have bombardment, vapor, moisture, teletron, and
microboard shape solid net studies within electron charging.
What this f and d reference is usually about is that there is
no previous data such as nuclear reactive specimen to study
and prove any theoretic properties. Very few materials have
the first required ingredient in describing a shield, data. In a
theoretical world where d is dextraxteon, and f is finitus reaction chain, then the material is described as alternatvie
iron group c making a mineral, a vitamin, and environment, a
full orbit, a magnet, a design. This would be theoretically
what we now have as the original shuttles to the moon, or
returned from planet landings. The d value will be known in
about 100 years. http://www.marstoday.com

Answer 2

talking as per the orbital boundry surface diagrams:
electron in d and f orbitals has a greater probability to be found farther from the nucleus thus on an average it spends more time at a greater distance from the nucleus than the corresponding s electron so they are poor sheilders of nuclear charge

Answer 3

Actually the d electrons are located at a greater distance from the nucleus so that the electrons are apart from each other... due to which they exert less repulsive force to each other.... the ans is the same .. lets consider the earth ,,, it attracts things in its gravitational field ... any thing near to it will experience more attractive force by the earth.... a thing away from it will have low g value.... that's same... some back to our point as same i explained that electrons at a greater distance from nucleus will have less effect on each other like d and f subshell electrons as compared with the s and p electrons.....

Answer 4

They are generally remote and their orbitals do not exist for significant volumes of space around the nucleus (shapes like balloons and dumbells leave unfilled volumes' having no shielding).

Answer 5

I'll guess: because the further out the electrons are the more loosely held they are by the magnetic bond with the neutron.