Can anyone help me?

Question

A construction company is planning to pour concrete for a driveway. The length of the the driveway is 16 ft longer than its width 'w'.
Write an expression for the area of the driveway.

Answer 1

The area = (16 + w)w = 16w + w^2.
where w is the width of the driveway.

Good luck with your new driveway.

Answer 2

One rule of thumb when trying to solve algebraic word problems is to determine the standard of comparison. That is, what are the unknowns being compared to? In this case, since the length of the driveway is 16 feet longer than its width w, the obvious standard of comparison is w.

Let w = width. Then
w + 16 = length of driveway.

Seeing as there's a length and width, it's obvious the driveway is a rectangle. The area of a rectangle is given by the formula length times width. That is,

A = (length) x (width)

However, we know what length is; it's (w + 16). And width is obviously w. Therefore

A = (w + 16) (w)

And if we wanted to simplify that, distribute the w over the brackets, to get

A = w^2 + 16w

Answer 3

w+16

Answer 4

A=wl=w(w+16)=w^2+16w

Answer 5

A = W (L + 16)

Answer 6

Area = width * length

Length = Width + 16 ft

Area = Width * (width + 16) = Width^2 + 16*Width

So the area function, where width is "w" is:

f(w)=w^2+16w

Answer 7

If 'w' stands for the width, then '(w+16)' stands for the length. Therefore, the area = w(w+16).

Answer 8

Ok. The formula for Area is A=lw, so your length is w + 16 and so your area is A=w(w+16) or the quadratic equation A=w^2+16w

By the way you should do your own homework.
This is my gift to you.

Answer 9

w(w+16)

Answer 10

w = width
l= length = w+16
A= ltimes width = w(w+16) = w^2+16w ft^2