PV=R[1-(1+i)^-n]/i
PV=$17,483.85
i=0.096/12
n=48
I had asked asked a question similar to this one and wondered if someone could help me out with this one to.
2006-12-24 06:02:18 · 14 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
PV=R[1-(1+i)^-n]/i
17483.85=R[1-(1+.008)^-48]/.00...
17483.35=R(1-1.008^-48)/.008
R=17483.85/(1-0.68217289389259...
R=17483.85*.008/0.317827106107...
R=$440.08/month
2006-12-24 09:02:31 · answer #1 · answered by mu_do_in 3 · 1⤊ 0⤋
6
2006-12-24 06:05:14 · answer #2 · answered by bbb 2 · 0⤊ 1⤋
PV=R[1-(1+i)^-n]/i
PV=$17,483.85
i=0.096/12
n=48
I assume you wish to solve for R
Then PV*i = R[1-(1+i)^-n]
17,483,85(.008) = R[1-(1.008)^-48]
13.9508 = R[1-(1.008)^-48]
13.9508= R(1-.682173)
13.9508 = R(.317827)
R= 13.9508/.317827
R= 43.894319
2006-12-24 06:22:53 · answer #3 · answered by ironduke8159 7 · 0⤊ 1⤋
Yea and for me curiously on non-math questions too bcs i take advantage of msn language on occasion too. And it takes faraway from ur self assurance. Lol, I have been on condition that punctation blunders when I wrote this reaction.
2016-10-05 23:36:28 · answer #4 · answered by ? 4 · 0⤊ 0⤋
R=2,9134894184302616230628228628562
2006-12-24 06:09:44 · answer #5 · answered by no_bsht 2 · 0⤊ 1⤋
17, 483.85 * 0.008 = R * (1 - (1.008)^-48)
139.8708 = R * .317827106
R = $440.0845532
2006-12-24 06:11:28 · answer #6 · answered by Allan 6 · 0⤊ 0⤋
Do you have a calculator
Solve for the unknown R
2006-12-24 06:03:59 · answer #7 · answered by ? 3 · 0⤊ 0⤋
Why would you need to know an answer to a question like that.
2006-12-24 06:05:31 · answer #8 · answered by ♥Sharon♥ 2 · 0⤊ 1⤋
R = -300.21375324364976644239343972627
2006-12-24 06:10:20 · answer #9 · answered by Doctor Gonzo 2 · 0⤊ 1⤋
sorry.. too much work for me to do.. I'm on Christmas break.. no math for me..
2006-12-24 06:09:40 · answer #10 · answered by 9*I ♥ Kasey Kahne*9 3 · 0⤊ 1⤋