multiply these binomials (2x-5)(x+3)what is the process of finding the answer.?

Question

what is the best way to remember to process of finding the answer to binominals

Answer 1

Remember, First Outside, Inside Last (FOIL).
2x times (x) = 2x squared
then 2x times 3 = 6x
then -5 times x = -5x
and -5 times 3 is -15
so you have 2x squared+6x-5x-15
or 2x squared +x-15

Did u understand what i did? I multplied the outside terms first, then the inside terms, and finally, i simplified. I hope this helps. If u use the FOIL method, u can't go wrong.

Hope this helps. Merry Christmas!!!

P.S. I got an A in Algebra, so relax. I know what i'm doing. if u need more help, send me an email at [e-mail] ok?

Answer 2

Just use FOIL. First,outside,inside, and last. It is basically distributing one binomial into the other. (2x+6)(3x+4)= FOIL F=first 2x and 3x are the first of each binomial. Multiply them together. (2x+6)(3x+4)=(6x^2) O=outside 2x and 4 are on the outside. Multiply. (2x+6)(3x+4)=(6x^2)+8x I=inside 6 and 3x are on the inside. Multiply. 2x+6)(3x+4)=(6x^2)+8x+18x L=last 6 and 4 are last. Multiply. (2x+6)(3x+4)=(6x^2)+8x+18x+24 Now just combine like terms. (2x+6)(3x+4)=(6x^2)+26x+24 6x^2+26x+24 A You can use this for any two binomials.

Answer 3

The FOIL thing is a crutch to make sure you make ALL the multiplications (4) that you're required. When the polynomials get longer, then will you make another "crutch"? For multiplying 2 binomials you could also use LOIF or LIOF.

But since answers are generally arranged in descending order of powers of one variable, something that will work always for multiplying 2 polynomials:

Arrange one polynomial in descending order of a chosen variable. Underneath that arrange the other polynomial in descending order (same variable). Start multiplying using one term in the bottom times each term in the top polynomial. (In the bottom polynomial it's usually expedient to use the rightmost term to start). Do the same with each term in the lower polynomial. As you form each partial product line, arrange similar/like terms under each other (after all, you're gonna combine them eventually. Finally, get your product from combining those columns of similar terms, quite similar to conventional natural number multiplication; except there's no place value involved.

example ( x^2 + xy + y ) (x - y)

x^2 + xy + y^2
00000+ x - y
----------------------------------
00+ (-x^2)y - xy^2 - y^3
x^3 + (x^2)y + xy^2
-----------------------------------
x^3 + 0 + 0 - y^3 or simply x^3 - y^3

(I had to use leading zeros to keep the terms in the partial products lined up. This illustration is a booger to display as I want it.)

Answer 4

You multiply each term in the first binomial by each in the second and add the products together.
2x * x = 2X^2
2x * 3 = 6x
-5 * x = -5x
-5* 3 = -15
add these 4 terms together,
2x^2+6x-5x-15 = (simplify to) 2x^2 + x - 15.

Answer 5

The FOIL method ...multiply the First rems in each set of parentheses by each other '2x' and 'x'. Then the Outside terms '2x' and '3'....then the Inside terms '-5' and 'x'...then Last terms "-5' and '3'....Combine your like terms...your answer should be 2x^2+x-15....a quadratic function.

Answer 6

A method that works whatever the number of terms:

(a + b)(c+d) = a(c+d) + b(c+d)

In your case:
(2x-5)(x+3) = 2x(x+3)-5(x+3)
From there, 2x^2 +6x -5x -15 = 2x^2 +x -15

This works even if there are 5 terms in the brackets:

(A+B+C+D+E)(F+G+H+J+K)= A(F+G+H+J+K)+
B(F+G+H+J+K)+C(F+G+H+J+K)
+D(F+G+H+J+K)+E(F+G+H+J+K)

It is the exact opposite of factoring. It may not be the fastest way, but it works.

Answer 7

Remember FOIL. First, Outer, Inner, Last. Multiply the first two terms, then the outer two, then the inner two, then the last two. Combine like terms and you have your answer! So, first you do 2x times x. Then 2x times 3. Then -5 times x, and then -5 times 3.

Answer 8

(2x-5)(x+3) if this is the question,first multiply 2x with x and 3.
the result will be 2x^2+6x.
now multiply -5 with x and 3.
the result will be -5x-15
combining both the results.
2x^2+6x-5x-15
the answer is 2x^2+x-15

Answer 9

For the first step, you want to multiply this part out:
2x(x+3)
2x^2+6x

For the next part, you want to multiply the next part out:
-5(x+3)
-5x-15

Now, put both of these parts together:
2x^2+6x-5x-15

Combine like terms:
2x^2+x-15 (that's your answer!)

Answer 10

The "FOIL" method:
1) multiply 'F'irst values (2x)(x)
2) multiply 'O'uter values (2x)(3)
3) multiply 'I'nner values (-5)(x)
4) multiply 'L'ast values (-5)(3)
Add.
This gets (2x^2) + (6x) + (-5x) + (-15).
Combine terms: 2x^2 + x - 15.
That's how I learned it.