2006-12-23 13:10:09 · 11 answers · asked by darshan 1 in Science & Mathematics ➔ Astronomy & Space
Don't believe these other answers - the sun has gravity and can be calculated easily. Please see the website below, enter your weight in the top box, and it will show your weight on the sun's graviational surface.
2006-12-23 13:23:37 · answer #1 · answered by Anonymous · 0⤊ 1⤋
My my my. such a simple question you would think.
Not so, could be because of your use of the word force.
There is the rub.
Some one said that you need two masses to calculate the gravitational force between them.
Well, yes and no.
In calculating the force of gravity on the surface of the earth (which we call g, or gravitational acceleration) the mass of the other object is not considered, since it is assumed that in comparison to the mass of the earth, the other mass is disreguraded.
That way we can use the formula Fg = G(m1*m2)/d^2 and totally disregard m2 without hurting its feelings.
However, we can not discount d (distance).
Lets run a check and plug in the figures for earth.
G= 6.67259E-11 m^3/s^2*kg
The mass earth is 5.97E+24 kg
The diameter of the earth is 12,756.30 KM
Ahhhh, an important point, the d^2 in the formula refers to the distance from Center to Center! So since we ignored the mass of the second object, we will also ignore its height about the surface of the earth, in fact, since I want to keep it simple, I am going to assume that the earth is a perfect sphere, no mountains or valleys to interfere in these calculations. Also, we need to divide the diameter by 2 to get the radius and also multiply it by 1000 to keep our units matching. So for d we are going to use 6,378,150 meters.
So we have Fg = 6.67259E-11* 5.97E+24/4.06808E+13 which comes out to 9.7954587925.
The units are canceled out until you have m/sec^2 left.
Which is pretty close to the actual figure (the actual figure does not assume that the earth is a sphere, and it measured at 45 deg. lat. at sea level).
Anyway, it is close enough for us to plug in the figures for the sun and see what we get.
Mass= 1.99E+30 kg
Diameter = 1,390,000.00 km
Using the formula we get 274.7638633611 m/sec^2.
So, that is what I would call the gravitational force of the sun.
2006-12-23 14:20:03 · answer #2 · answered by Walking Man 6 · 0⤊ 0⤋
Since the mass of the Sun is 332,946 times the mass of the Earth, it has 332,946 times the gravity. But that difference is as measured at the same distance. For example, the gravity of Earth as measured 1 million miles from the center of the Earth is 332,946 times weaker than the gravity of the Sun measured 1 million miles from the center of the Sun.
Some people may want to know the difference on the surface of he Sun compared to the Surface of the Earth. Since the Sun is much larger than Earth, and its "surface" is much farther from its center than Earth's surface is from its own center, the difference is much less than 332,946 times. In fact, it is only 27 times.
Technically, ramshi is correct, you need two masses for there to be a gravitational force. But the acceleration of gravity is independent of mass. Also, you can use a test mass, say 1 kilogram, to measure the force of gravity of any planet or star.
2006-12-23 13:17:10 · answer #3 · answered by campbelp2002 7 · 1⤊ 0⤋
Gravitational force of one isolated body is not defined (in Newton's Law of Universal Gravity). Even in Relativity, gravity is just curvature of space. So, there is no such thing as gravitational force of an isolated body. It will be there only if two bodies exist and is the force of attraction bewteen them.
Gravitational force between two bodies is defined as being proportional to the product of the two masses divided by square of distance.
2006-12-23 13:16:24 · answer #4 · answered by ramshi 4 · 1⤊ 0⤋
The moon would not revolve around the sunlight because of the fact the gravitational pull of the Earth is larger the place the moon is. constructive, the sunlight does have a large gravitational rigidity, yet there's a cut back. otherwise, the Earth could fall in the direction of it somewhat than rotate around it.
2016-11-23 14:05:42 · answer #5 · answered by ? 4 · 0⤊ 0⤋
I just want to elaborate because there is a lot of incorrect information flowing through these answers.
Gravity is a force between TWO masses. So there is no 'gravitational force' of the sun. It depends on distance, and a second mass.
The formula is:
F = G * m1 * m2 / r^2
So, you can't express the force of the sun with a scalar, but you can in terms of a function - but a function of two variables.
F(m, r) = 6.673E-11 * 2E30 * m / r^2
G = 6.673E-11 and Msun = 2E30
2006-12-23 13:35:45 · answer #6 · answered by dgbaley27 3 · 0⤊ 1⤋
there is very little
gravitional force from
the sun the suns gravitional froce
can kepp the plants in orbit and move
2006-12-23 13:33:33 · answer #7 · answered by Melissa H 1 · 0⤊ 0⤋
I don't know the exact figure, but it must be huge in order to hold the solar system together.
I found that its mass is 333,444 times the mass of the Earth.
Gravity acceleration "g" of the Earth is 9.8 m/s² or 32.17 ft/s².
The gravity Force exerted on a body is given by F=mg where m is the mass of the object and g the gravity.
2006-12-23 13:34:23 · answer #8 · answered by PragmaticAlien 5 · 0⤊ 0⤋
If you were near the surface of the sun its gravitational force acting on you would be 165.6675 meters/sec/sec For contrast, on the surface of Earth the gravitational force acting on you is about 9.8 meters/sec/sec
2006-12-23 13:18:20 · answer #9 · answered by Chug-a-Lug 7 · 2⤊ 0⤋
the sun is in space there is no gravity there
2006-12-23 13:11:49 · answer #10 · answered by Princess1988 1 · 0⤊ 3⤋