An airplane is descending to an airport to land. The airplane is at 30,000 feet. If the airplane descends at a 3 degree angle of depression, how far is the airport from the ground directly below the plane?
I've done the problem but want to make sure it is correct.
Thanks
2006-12-23 11:09:46 · 5 answers · asked by bravestdawg101 3 in Science & Mathematics ➔ Mathematics
Use tan 3 degrees = 30 000/x
This gives x = 30000/tan 3
x = 572434.1
2006-12-23 11:14:12 · answer #1 · answered by keely_66 3 · 2⤊ 0⤋
L = 30000 / tan 3°
L= 572434 ft
OR
L = 30000 * tan 87°
L = 572434 ft
as shown in this link
2006-12-23 14:45:03 · answer #2 · answered by M. Abuhelwa 5 · 1⤊ 0⤋
tan(3)=30,000/x
Multiply x from both sides:
tan(3)x=30,000
Divide tan(3) from both sides:
x=30,000/tan(3)
x=572434.1 ft.
keely_66 does have the right answer.
2006-12-23 11:50:58 · answer #3 · answered by Anonymous · 1⤊ 0⤋
tan 3° = 30,000/x
x = 30,000/tan 3° = 572,434.1 feet = 108.4 miles
2006-12-23 11:20:08 · answer #4 · answered by Northstar 7 · 2⤊ 0⤋
keely_66 is right.
2006-12-23 11:19:38 · answer #5 · answered by Anonymous · 2⤊ 0⤋