6xy-8x+15y-20 is the polynomial. But is it possible to factor it? It seems like it is already factored for you. Can someone please help? thank you
2006-12-23 07:54:00 · 11 answers · asked by baseballman1243 1 in Science & Mathematics ➔ Mathematics
6xy - 8x + 15y - 20=
2x(3y - 4) 5(3y - 4)=
(2x+5) (3y-4)
2006-12-23 07:59:47 · answer #1 · answered by RScott 3 · 5⤊ 0⤋
First: with 4 terms > group "like" terms >>>
(6xy + 15y) - (8x - 20)
Second: factor each set > find a least common factor >>>
3y(2x + 5) - 4(2x + 5)
Third: combine one inner term with the outer term:
= (2x + 5)(3y - 4)
2006-12-23 11:45:52 · answer #2 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
Yes and here it is:
Change it around like this
15y + 6xy - 8x - 20
then easy factor and factor again
3(5y+2xy) - 4(2x+5) = 3y(2x+5) - 4(2x+5) = (2x+5)(3y-4)
2006-12-23 08:01:39 · answer #3 · answered by kellenraid 6 · 3⤊ 0⤋
6xy-8x+15y-20 =
2x(3y - 4) + 5(3y - 4) =
= (2x + 5)(3y - 4)
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2006-12-23 11:47:01 · answer #4 · answered by aeiou 7 · 0⤊ 0⤋
factor 2 x out from the first two terms and 5 from the second two terms
2x (3y -4) + 5 (3y -4)
(2x + 5) x (3y-4)
2006-12-23 09:54:02 · answer #5 · answered by MrWiz 4 · 1⤊ 0⤋
6xy-8x+15y-20
= 2x (3y - 4) + 5(3y - 4)
= (3y - 4)(2x + 5)
2006-12-23 08:00:52 · answer #6 · answered by Sheen 4 · 3⤊ 0⤋
combine your like terms
6xy-8x+15y-20 = -8x+21y-20
then factor, i'd use the quadratic equation for this one, but when you get to simplify the equation under the square root you find that you get a negative and you can't square root a negative, unless you use imaginary numbers. I don't know if you teacher allows you to use those or if u even know what those are.
2006-12-23 10:16:44 · answer #7 · answered by drunken_warrior 1 · 0⤊ 1⤋
question a million: Reorder the words: -36 + -48x + -16x2 ingredient out the terrific person-friendly ingredient (GCF), '-4'. -4(9 + 12x + 4x2) ingredient a trinomial. -4((3 + 2x)(3 + 2x)) very end result:-4(3 + 2x)(3 + 2x) in case you're able to desire to resolve 2x + 3 = 0 x = -3/2 question 2: 4w^2 - 256 4(w^2 - sixty 4) in case you're able to desire to resolve w^2 - sixty 4 = 0 w^2 = sixty 4 w = 8 or -8
2016-11-23 13:35:03 · answer #8 · answered by Anonymous · 0⤊ 0⤋
No, it can be factored into two binomials, but I'm too lazy to do it. I can tell you that it will look like:
(3x+/-some#)(2y+/-some#)
2006-12-23 08:01:54 · answer #9 · answered by Anonymous · 3⤊ 2⤋
2x(3y-4)+5(3y-4)
(2x+5)(3y-4)
2006-12-23 08:07:34 · answer #10 · answered by Anonymous · 2⤊ 0⤋