math help needed?

Question

2. How would the number 68 be writtenin binary notation?
If 1101 is written in binary notation, how would it be written in decimal notation, and lastly which is true of a rational number
a. it is always the root of an algebraic equation with integer coefficients.
b. Its decimal always begins to repeat itself eventually
c. You can find an integer which when multiplied by the number, gives another integer, or
d. all of these

Answer 1

2. Keep dividing by 2 until you get a quotient less than 2.
Let me abbreviate this by writing down the remainder
with the quotient next to it:
34 0
17 0 0
8 1 0 0
4 0 1 0 0
2 0 0 1 0 0
1 0 0 0 1 0 0
The answer is 1000100.
To write 1101 in decimal you must think
of each place from right to left as the
next power of 2, so 1101_2 = 1 + 4 + 8 = 13.
Finally, a,c,d are true. b is false.
Let's prove these:
a: Let the rational number be x = a/b, where a and b are integers.
and b isn't zero.
if x = a/b, then x is a root of bx-a = 0.
b. This is false because the decimal may terminate.
1/2 = 0.5
c. If x is not an integer, then b*a/b gives another integer.

Answer 2

68=64+4 = 1*64+0*32 +0*16+0*8 +1*4+0*2+0*1 = 1000100 in binary

1101 in binary = 1*8+1*4+0*2+1*1 = 8+4+1 = 13

Option D all the above

Answer 3

-68^

Answer 4

b i think b is the answer

Answer 5

I think B is the best answer!!!!!!!!!

Answer 6

try this

Answer 7

d. all of these