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My teacher told me that square root of negative 1/4 = plus/minus half i. Is this correct? I thought that only when s^2=5 then s=+/- square root 5 but when or nvm.

Please explain and any examples would be appreciated.

2006-12-23 04:09:07 · 11 answers · asked by Anonymous in Science & Mathematics Mathematics

11 answers

teacher knows best

2006-12-23 06:08:18 · answer #1 · answered by Anonymous · 0 0

1/2 x 1/2 = 1/4 so +/-1/2 is the square root of 1/4. Since it is negative and the square of -1 = i the answer is +/-1/2 i.

2006-12-23 04:12:50 · answer #2 · answered by Barkley Hound 7 · 0 0

I believe the focus of your question is on the +/- 2. This simply means that both +2 and -2 when squared, give you +4. And of course, the imaginary 'i' is there because you cannot take the square root of a negative number. If you were to plot the equation y = x^2 on graphic paper, you would get a parabola and 2 of the points on the parabola would be (2, 4) and (-2, 4). Any equation of the second degree (i.e. the highest exponent is 2) produces a parabola which confirms that for each value of y, there are 2 values of x; Except for the maximum or minimum point which is usually found by taking the derivative of the equation.

2016-05-23 01:52:38 · answer #3 · answered by Anonymous · 0 0

? What is nvm?
Your teacher is right on, almost!
Look at it this way:
The positive square root of 1/4 is 1/2. The
negative square root of 1/4 is -1/2.
If we want the 2 square roots of -1/4 we
must multiply the 2 values above by √-1 or i.
So the 2 square roots of -1/4 are 1/2*i
and -1/2*i.

2006-12-23 04:21:52 · answer #4 · answered by steiner1745 7 · 0 0

Your teacher is correct.

In your second sentence, you also are correct... up to "...but ". After that I don't know what you're saying.

Square roots (or even roots) of negative numbers numbers don't exist within the real no. system. Including the imaginary (or non-real) number system provides answers. (The two taken together -- real and non-real --
make the complex number system.)

i = one of the sqrt of (-1)
plus or minus i^2 = -1
i^3 = -i
i^4 = 1

Thus any power of i simplifies to one of these 4 forms; and the real numbers have been expanded by the imaginary to become the complex, where all numbers are considered to be of the form: a + bi, where a and b are real number coefficients.

2006-12-23 04:28:52 · answer #5 · answered by answerING 6 · 0 0

That is correct because i stands for imaginary numbers. In math you are not supposed to take the square root of a negative number. Thats why you add i. i= square root of -1, i squared = -1, i to the fourth= 1.

2006-12-23 04:13:57 · answer #6 · answered by Aisha B 1 · 0 0

That´s right because:
(-1/2) x (-1/2) = +1/4 = 1/4
or
(+1/2) x (+1/2) = +1/4 = 1/4

A positive number as element of R has two roots: one is negative and another is positive.
Kisses!

2006-12-23 04:26:16 · answer #7 · answered by aeiou 7 · 0 0

Yes.

If you multiply (1/2)i by itself, and use iXi = -1, you get 1/4. Check the other answer the same way.

Here is another example: x^2 = -9

x = 3i or x = -3i.

Here is another, related, example:

X^2 = + 9

x = 3 or -3.

2006-12-23 04:16:44 · answer #8 · answered by Asking&Receiving 3 · 0 0

Yup - it's good to know she got it right.

1/2 times 1/2 is a quarter, so the sq rt will contain1/2 (+ or -)

A negative number must have i in its sq rt.

1/2i times 1/2i = -1/4

or -1/2i times -1/2i = -1/4

Good luck and well done for being so industrious over Xmas

2006-12-23 04:26:09 · answer #9 · answered by rosie recipe 7 · 0 0

Yes. That is correct. Because Sqr(-1/4) =sqr(1/2i)^2=+-1/2i Ans.

2006-12-23 04:20:11 · answer #10 · answered by aminnyus 2 · 0 0

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