Sum of interior angles for any polygon = (n-2)*180
where n is the number of sides.
So for a pentagon, (5-2)*180 = 540 degrees
Total angles in pentagon is 5
THerefore each angle measures 540/5 = 108 degrees.
You can apply this formula for any figure like triangle, square, hexagon, etc.
All the very best!!
2006-12-23 00:53:20
·
answer #1
·
answered by Venkateswaran A 2
·
1⤊
0⤋
The link under may be useful to you. the sum of the interior angles of a polygon = one hundred eighty (n-2) the place N is the form of sides. for a pentagon one hundred eighty(5-2)= one hundred eighty x3 =540 for a conventional pentagon all angles are equivalent. as a result: 540/5 =108 stages.
2016-10-18 22:05:18
·
answer #2
·
answered by janovich 4
·
0⤊
0⤋
each interior angle measures 108 degrees provided it is a regular pentagon ie all 5 sides equal and all 5 angles equal.
2006-12-23 03:02:55
·
answer #3
·
answered by Nagarajan S 1
·
0⤊
0⤋
The formula is 180(n-2) where n is the number of angles.
180*3=540°
2006-12-23 06:19:55
·
answer #4
·
answered by mu_do_in 3
·
0⤊
0⤋
well in a pentagon,the sum of all the interoior angles = 540
so each angle in regular pentagon, where all sides are equal and all angles are equal is108°.
hope it helps
2006-12-23 00:55:31
·
answer #5
·
answered by For peace 3
·
0⤊
0⤋
120 degrees
2006-12-23 00:49:40
·
answer #6
·
answered by wind cries mary 3
·
0⤊
0⤋
interior angle=(1/n)[(n-2)*pi]
=(1/5)[(5-2)pi]
=1/5*3pi
=108*
2006-12-23 00:56:29
·
answer #7
·
answered by raj 7
·
0⤊
0⤋
you can use the formula (n-2)*180 only if it is a regular polygon(all sides same).
2006-12-23 00:57:17
·
answer #8
·
answered by Jon 3
·
0⤊
0⤋