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8 answers

Sum of interior angles for any polygon = (n-2)*180
where n is the number of sides.

So for a pentagon, (5-2)*180 = 540 degrees
Total angles in pentagon is 5

THerefore each angle measures 540/5 = 108 degrees.

You can apply this formula for any figure like triangle, square, hexagon, etc.

All the very best!!

2006-12-23 00:53:20 · answer #1 · answered by Venkateswaran A 2 · 1 0

The link under may be useful to you. the sum of the interior angles of a polygon = one hundred eighty (n-2) the place N is the form of sides. for a pentagon one hundred eighty(5-2)= one hundred eighty x3 =540 for a conventional pentagon all angles are equivalent. as a result: 540/5 =108 stages.

2016-10-18 22:05:18 · answer #2 · answered by janovich 4 · 0 0

each interior angle measures 108 degrees provided it is a regular pentagon ie all 5 sides equal and all 5 angles equal.

2006-12-23 03:02:55 · answer #3 · answered by Nagarajan S 1 · 0 0

The formula is 180(n-2) where n is the number of angles.
180*3=540°

2006-12-23 06:19:55 · answer #4 · answered by mu_do_in 3 · 0 0

well in a pentagon,the sum of all the interoior angles = 540
so each angle in regular pentagon, where all sides are equal and all angles are equal is108°.
hope it helps

2006-12-23 00:55:31 · answer #5 · answered by For peace 3 · 0 0

120 degrees

2006-12-23 00:49:40 · answer #6 · answered by wind cries mary 3 · 0 0

interior angle=(1/n)[(n-2)*pi]
=(1/5)[(5-2)pi]
=1/5*3pi
=108*

2006-12-23 00:56:29 · answer #7 · answered by raj 7 · 0 0

you can use the formula (n-2)*180 only if it is a regular polygon(all sides same).

2006-12-23 00:57:17 · answer #8 · answered by Jon 3 · 0 0

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