If r is the remainder when 80 is divided by 9 and n is the remainder when r is divided by 3, what is the value of rn?
2006-12-22 15:42:42 · 13 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
rn is (r)(n) not m
2006-12-22 15:43:12 · update #1
80/9 = 8 remainder 8
8/3 = 2 remainder 2
r is 8 and n is 2 so (r)(n) is 16
2006-12-22 15:46:07 · answer #1 · answered by Anonymous · 1⤊ 0⤋
If r is the remainder when 80 is divided by 9 and n is the remainder when r is divided by 3, what is the value of rn?
given this information, 80/9= 8r8. so, r=8. 8/3= 2r2, so n=2 and rn= 8x2= 16 is your answer
2006-12-23 00:14:17 · answer #2 · answered by pursuit_of_happyness 3 · 0⤊ 0⤋
80/9 =8 with a remainder of 8
8/3 =2 with a remainder of 2
2x8 =16
2006-12-22 23:52:34 · answer #3 · answered by James O only logical answer D 4 · 0⤊ 0⤋
80 divided by 9 gives you 8 with remainder 8, so r is 8. When 8 is divided by 3, you get 2 with remainder 2, so n is 2. Then r x n is 8 x 2, so it's 16.
2006-12-22 23:48:42 · answer #4 · answered by Sephisabin 3 · 0⤊ 0⤋
80/9=72 so the remainder is 8. 8/2=6 so the remainder is 2. 8x2=16. rn=16.
2006-12-23 00:02:42 · answer #5 · answered by witch_girl23 2 · 0⤊ 0⤋
80/9 = 8 with remainder 8 ( call that r)
and , if r= 8 and 8/3 = 2 with remainder 2 (call that n)
then r*n = 16
2006-12-22 23:46:25 · answer #6 · answered by bkc99xx 6 · 0⤊ 0⤋
80/9 = 8 with remainder r = 8
r/3 = 8/3 = 2 with remainder n = 2
r(n) = 8*2 = 16
2006-12-23 00:09:24 · answer #7 · answered by Northstar 7 · 0⤊ 0⤋
16
2006-12-23 16:20:44 · answer #8 · answered by plain person 1 · 0⤊ 0⤋
16
2006-12-23 06:55:34 · answer #9 · answered by Anonymous · 0⤊ 0⤋
16
2006-12-22 23:51:35 · answer #10 · answered by beckybunniboo 1 · 0⤊ 0⤋