A gourmet food shop mixes nuts selling at $16/lb with fruit selling at $3/lb. They want a mixture of 7 lb. to sell at $12/lb. How many pounds of each should they use?
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I have no idea what to do. Wow, I feel so dumb :(
2006-12-22 12:41:18 · 3 answers · asked by Anonymous in Education & Reference ➔ Homework Help
Let $16 nuts = x
Let $3 nuts = 7 - x
The basic equation is
cost x amount + cost x amount = cost x amount
$16 (x) + $3 (7 - x) = $12 x 7
16x + 21 - 3x = 84
13x + 21 = 84
13x = 63
x = 4.85
You would use 4.85 pounds of $16 nuts with (7 - 4.85) or 2.15 pounds of $3 fruit to get your mixture 7 pounds of $12.
2006-12-22 15:40:55 · answer #1 · answered by Tori 3 · 2⤊ 0⤋
total mixture=7 lb
let quantity of nuts at rate $16/lb =x lb
therefore quantity of fruits at rate of $3/lb=7-x
according to question
16x+3(7-x)=12*7
16x+21-3x=84
13x=84-21
13x=63
x=63/13
=4.85lb nuts
7-4.85=2.15 lb fruit
2006-12-22 23:24:10 · answer #2 · answered by flori 4 · 0⤊ 0⤋
you may in basic terms upload the equations together and it will get rid of the y thus. 4x +3y = a million +2x-3y = a million =6x=2 Divide to get x = 2/6 = a million/3. Now plug in x in between the equations to remedy for y. 4(a million/3) + 3y = a million 4/3 + 3y = a million 3y = -a million/3 y = -a million/9. If the difficulty replaced into extra reliable, you will would desire to multiply between the equations through a quantity to get a gadget in which you would be able to upload/subtract to cancel a variable.
2016-12-15 06:30:09 · answer #3 · answered by ? 4 · 0⤊ 0⤋