Write a balanced equation for the decomposition of mercury (II) oxide.
2006-12-22 12:32:58 · 6 answers · asked by chemistrystudentinneed 1 in Science & Mathematics ➔ Chemistry
2 HgO = Hg + O2
2006-12-24 14:51:04 · answer #1 · answered by ibrar 4 · 2⤊ 0⤋
If it is "decomposing" that means it breaks apart into separate elements. Since "mercury (II) oxide" consists of mercury and oxygen, it must decompose into those two elements!. Oxygen is diatomic and will be written as O2, not just O.
2 HgO = Hg + O2
2006-12-23 05:01:45 · answer #2 · answered by The Old Professor 5 · 0⤊ 0⤋
2 HgO --> O2 + 2 Hg
2006-12-22 12:34:50 · answer #3 · answered by Xiangwei Xi 3 · 1⤊ 0⤋
Do your own homework
2006-12-22 12:34:40 · answer #4 · answered by yodadoe 4 · 0⤊ 3⤋
2HgO(s) --> 2Hg(l) + O2(g)
2006-12-22 12:43:13 · answer #5 · answered by stewartlucas467 2 · 0⤊ 0⤋
2HgO(s) ---> O2(g) + 2Hg(l)
Im such a loser...
2006-12-22 12:37:29 · answer #6 · answered by Kuba 2 · 0⤊ 0⤋