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10 answers

I think that you also need to take air friction into account, because any object will reach a "terminal" velocity.
If you don't care about this, you only need to know how long, t, it's been falling, and the speed will be t*9.8 m/s (where t is time in seconds).

I think the terminal velocity of a human is about 120 mph. The reason I know that is that vertical wind tunnels, used for sky diving practice, have the wind speed set to 120 mph.

2006-12-22 12:17:05 · answer #1 · answered by firefly 6 · 0 0

I don't think any of the answers were all that correct so far. Acceleration is distance/second^2. On earth it is 9.8 m/s^2. Velocity is distance/second.

So to get a velocity from acceleration you multiple the acceleration by time.

So the time (t) times the acceleration (a) gives the velocity (v).

On Earth, the speed of a freefalling object as a function of time is
v(t) = a*t.

In terms of air friction, which leads to a terminal velocity. I feel your question was referring to the basic principle of v = at. I assume you're taking Physics 1, and that type of question rarely takes friction into account.

2006-12-22 19:57:15 · answer #2 · answered by dgbaley27 3 · 2 1

The instantaneous velocity of any object, regardless of mass and ignoring air resistance, is given by the acceleration of gravity multiplied by how long it has been falling, namely v = a * t.

2006-12-22 21:22:29 · answer #3 · answered by hznfrst 6 · 0 0

Assuming that there is no friction;

The speed at any point is determined by noting the time for the body to fall up to that point.

V = g t. where g is the acceleration due to gravity.
-----------------------------------------Or---------------------------
The speed at any point can be determined by measuring the distance of that point from the initial position.

V = square root of 2g H.

Thus either by measuring the time or by measuring the distance of travel we can calculate its velocity.

2006-12-22 21:27:25 · answer #4 · answered by Pearlsawme 7 · 1 0

Free falling is measured 9.8m/s2. Every second times by 9.8

2006-12-22 19:46:10 · answer #5 · answered by I love mode! 2 · 1 0

you can calculate it based of the acceleration of gravity

g=9.81 m/s^2

v(final)^2=v(original)^2 + 2*gravity*distance traveled

2006-12-22 19:49:36 · answer #6 · answered by Anonymous · 1 0

in basic 9.8 meters per second, squared.

first second, 9.8
second second 9.8 * 9.8
third 9.8*9.8*9.8
and so on
up to the max speed of 1 g.
of course air friction will slow you some
depends on the level of science you are looking at.

2006-12-22 19:46:24 · answer #7 · answered by papeche 5 · 0 4

a = 32ft/s^2

you would also need to factor in air resistance

2006-12-22 19:47:47 · answer #8 · answered by Gary L 2 · 0 2

32' per second , per second squared

2006-12-22 19:39:24 · answer #9 · answered by spitfin 3 · 1 2

by knowing it's mass, height and of course acceleration due to gravity..

2006-12-22 19:44:32 · answer #10 · answered by George 3 · 1 4

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