13.Use this reaction for the following questions: CI(g)+2HBr(aq) ------2HCI(aq)+Br2(I)
a.Determine the oxidation numbers of each element in both the reactants and the products of this oxidation reduction reaction of chlorine and bromic acid.(6 points).
b.Which element is oxidized in this reaction?(2 points)
c.Which element is reduced in the reaction? (2 points).
2006-12-22 10:54:26 · 5 answers · asked by kittyvamptress 2 in Science & Mathematics ➔ Chemistry
First of all the equation you've presented is incorrect. It should read Cl2 (g) + 2Hbr (aq) ---> 2HCl (aq) + Br2 (l). You forgot to put a two after chlorine on the left hand side.
The oxidation number of chlorine on the left hand side it 0, since it's in its natural form. The oxidation number of hydrogen on the left hand side is +1, since it gives up its electron to bromine. Therefore the oxidation number of bromine on the left hand side has to be -1, since it accepts an electron from hydrogen.
The oxidation number of hydrogen on the right hand side is +1, since it gives up its electron chlorine. Therefore the oxidation number of chlorine on the right hand side is -1, since it accepts an electron from hydrogen. The oxidation number of bromine on the right hand side is 0, since it's in its natural from i.e the charge on its 0.
Oxidation is defined as the loss of electrons. Since bromine looses it extra electron and returns to its natural state it has been oxidized.
Reduction is defined as the gain of electrons. Since chlorine has an extra electron it has been reduced.
2006-12-22 12:03:04 · answer #1 · answered by iamdaroot 2 · 0⤊ 0⤋
I in I2 = 0 I in I- = -1 S2O3-- set O to -2 ==> S2 has to offset -6 -2 = -8 so S is +4 edit: Soc STANDS by this answer the OVERALL oxidation numbers add up to the overall charge S+3 and O-2 in above would imply S2O3-- has a charge of zero but it is -2 S4O6-- O=-2 S=+7
2016-05-23 16:46:24 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Cl(g) oxidation number is 0, since it is a pure element.
H(g) oxidation number is 0, since it is a pure element, Br oxidation number is -1., H oxidation number is +1, Cl oxidation number is -1, Br2 oxidation number is 0(pure element).
Cl is being reduced.
Br in HBr is being oxidized.
2006-12-22 12:24:26 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Cl is being reduced
and Br is being oxidized
yup
2006-12-22 11:06:41 · answer #4 · answered by chanti 3 · 0⤊ 0⤋
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2006-12-22 10:59:28 · answer #5 · answered by unnamed 1 · 1⤊ 1⤋