if f(x)=x^2-4x+3 & g(x)=2x-1,solve f(x)=F(g) and find the value of gf(2)?

Answer 1

f(x)=x^2-4x+3 & g(x)=2x-1,

gf(x)
=g(x^2-4x+3){do the f operation}
=2(x^2-4x+3)-1{do the g operation}
=2x^2-8x+6-1
=2x^2-8x+5

therefore,
gf(2)=2*4-8*2+5
= -3

i hope that this helps

Answer 2

The y intercept would have an x coordinate of 0, so substitute the form 0 for the variable x 4y - 3 = 4x will become 4y - 3 = 4(0) will become 4y - 3 = 0 will become 4y = 3 will become y = 3/4 The y intercept is 3/4

Answer 3

Hang on!
I thought if f(x) = x^2-4x+3, then g(x) = 2x-4

Answer 4

f(x) = f(g)


x^2-4x+3=(2x-1)^2-4(2x-1)+3
= 4x^2+1-4x-8x+4+3
= 4x^2-12x+8
0 = 3x^2-8x+5
0 = 3x^2-3x-5x+5
0 = 3x(x-1)-5(x-1)
0 = (3x-5)(x-1)

1)3x-5 = 0
x = 5/3
2)x-1 = 0
x = 1

Answer 5

1.

Answer 6

for that last one, x=g take off the f's. 2g= -1 using distributive property for the second to last one, with x=g that means 2x = -1. so g & x = -.5. so (-0.5)(-0.5)(2) the negative cross each other out so the answer is positve. .5 and .5 equals .25. .25 times two is .5. The answer is 0.5, positive.

Answer 7

f(x) = x^2 - 4x + 3
g(x) = 2x - 1

f(2) = 2^2 - 4(2) + 3 = 4 - 8 + 3 = -4 + 3 = -1
g(f(2)) = g(-1)

g(-1) = 2(-1) - 1 = -2 - 1 = -3

ANS : g(f(2)) = -3

Answer 8

Pre calculus....this stuff used to give me fits but eventually I mastered it. Sadly that was twenty years ago.... I remember almost nothing about it. Its true what they say... if you don't use it you'll lose it.

Answer 9

f(x)=x^2-4x+3
g(x)=2x-1

F(x)=F(g)
x=g

g(f(2))=g(2^2-4(2)+3)
g(f(2))=g(-1)

g(-1)=2(-1)-1
g(-1)=-3

g(f(2))= -3

Answer 10

ive not done maths since alevel and all the weed i smoked at uni made me forget it all