The molar mass of Fe2(SO4)3 is 399.91 g/mol. How do you figure this stuff out?
2006-12-22 06:44:07 · 5 answers · asked by sydney 2 in Science & Mathematics ➔ Chemistry
First determine the number of moles of sulfate that you have.
3.47 x 10^24/ (6.022 x 10^23)
Then multiply by the fraction of mols of iron (III) sulfate per moles of sulfate
X 1mol iron(III) sulfate/3mol SO4
Then multiply by the molar mass of iron (III) sulfate
x 399.91 g Iron (III) sulfate/1mol = 768g
Be sure to check my math...;>}
Rots of Ruck, Dude
2006-12-22 06:55:52 · answer #1 · answered by docrider28 4 · 0⤊ 0⤋
42
2006-12-22 06:45:42 · answer #2 · answered by Anonymous · 0⤊ 0⤋
42
2006-12-22 06:44:56 · answer #3 · answered by Mr. Goodkat 7 · 0⤊ 0⤋
Those mobile trailer homes that are always parked in the Wal-Mart parking lot, knock on their door, they always know the answers to stuff like that.
2006-12-22 06:47:51 · answer #4 · answered by double D 2 · 0⤊ 0⤋
dude!!! is that like science /math or somethin?
2006-12-22 06:45:24 · answer #5 · answered by yo! wuzzup! =) 2 · 0⤊ 0⤋