2006-12-22 06:30:18 · 7 answers · asked by wicked 1 in Science & Mathematics ➔ Mathematics
Law of sines
7/11=sin B/sin 34
sin B=7 sin 34/11=0.3558500294813843464657269981729
B=arcsin 0.3558500294813843464657269981729
B=21°
2006-12-22 06:42:58 · answer #1 · answered by mu_do_in 3 · 3⤊ 0⤋
Hi,
You can use the Law of Sines, which says that Sine A/a = Sine B/b. For your problem, that would be sin(34)/11 = sin(B)/7. Cross multiplying to solve this would give 7sin(34)/11 = sin(B). This would give you that .3559 = sin(B). TO find angle B in degrees, find the inverse sine of .3558 by putting sin^-1(.3558) into your calculator. You will get 20.8455 which rounds to 21 degrees for your angle B.
2006-12-22 14:48:13 · answer #2 · answered by Pi R Squared 7 · 3⤊ 0⤋
By the law of sines.
a/sinA = b/sinB
asinB = bsinA
sinB = (b/a)sinA = (7/11)sin 34° = 0.35585
B = arcsin[(7/11)sin 34°] = arcsin(0.35585) = 21°
2006-12-22 16:51:37 · answer #3 · answered by Northstar 7 · 1⤊ 0⤋
Use the Law of Sines:
sin(α)/a=sin(β)/b=sin(γ)/c
sin(34)/11=sinB/7.0
sinB=(sin(34)x7.0)/11
sinB=.3559
B=arcsin(.3559)=20.8=21°
2006-12-22 15:14:01 · answer #4 · answered by Anonymous · 2⤊ 0⤋
(11/sin(34)) = (7/sinB)
sin(B) = 7/(11/sin(34))
sin(B) = (7sin(34))/11
B = 21°
2006-12-22 18:56:29 · answer #5 · answered by Sherman81 6 · 1⤊ 0⤋
angle B=56
line c= 6.16
2006-12-22 15:21:22 · answer #6 · answered by Lucy A 2 · 1⤊ 0⤋
5.40
2006-12-22 15:34:20 · answer #7 · answered by Anonymous · 0⤊ 2⤋