2006-12-22 05:36:27 · 7 answers · asked by atljasmine4 1 in Science & Mathematics ➔ Chemistry
Yes.
Bromine has a radius of 114 pm, while Fluorine has a radius of 72 pm.
Others have reported the radii as 115 pm and 70 pm respectively.
2006-12-22 05:40:15 · answer #1 · answered by Richard 7 · 16⤊ 1⤋
The atomic radius of Bromine (Br) is greater than that of Fluorine (F) because it has more atomic sub-shells. This is not always the case, as Li will have a smaller radius than He when Li is an ion (not in base atomic state). In general, larger to the left, larger towards the bottom.
2006-12-22 13:46:07 · answer #2 · answered by Mr. Chemistry 2 · 1⤊ 0⤋
If you write the electron configuration for Br, the last level you use is level 4. If you write the electron cofiguration for F, the last level you use is 2. If electrons occupy higher levels (4 for Br) the atom must be bigger.
2006-12-22 16:26:46 · answer #3 · answered by The Old Professor 5 · 0⤊ 0⤋
Yes, Bromine is 114 picometers in radius and Flourine is only 64. This is because of the addition of electron shells as you move down the table.
2006-12-22 13:42:37 · answer #4 · answered by prittykitty22389 2 · 0⤊ 0⤋
yes, as you go down a row of the periodic table the atomic radius increases
2006-12-22 13:39:00 · answer #5 · answered by jdog33 4 · 0⤊ 0⤋
No it does not, because FLuorine's ionic radii is way larger.
2006-12-22 13:41:04 · answer #6 · answered by chanti 3 · 0⤊ 2⤋
yes it does
2006-12-23 00:34:02 · answer #7 · answered by Kelly Bundy 6 · 0⤊ 1⤋