2006-12-22 05:15:41 · 7 answers · asked by atljasmine4 1 in Science & Mathematics ➔ Chemistry
No. The radius of the ion is 152 pm while the radius of the atom is 227 pm.
2006-12-22 05:37:11 · answer #1 · answered by Richard 7 · 15⤊ 1⤋
A K atom has 19 protons and 19 electrons.
A K+ ion has the same 19 protons, but only 18 electrons, and one less main level.
The remaining electrons are much more strongly attracted to the nucleus, and the ionic radius is much smaller than the atomic radius.
2006-12-22 05:48:33 · answer #2 · answered by Gervald F 7 · 1⤊ 0⤋
K has total19 electrons(2,8,8,1) so it has total 4 electron shells,while K+ has 18 electrons (2,8,8) and has 3 electron shells.
as the number of shells decreases the atomic radius decreases.
so K+ does not larger atomic radius than K.
2006-12-23 06:57:29 · answer #3 · answered by akshay p 1 · 0⤊ 0⤋
I would think not. Removing an electron may have the opposite effect. The atomic radius is largely the result of how strongly the electron cloud is attracted to the nucleus. Removing an electron (forming a + ion) is not going to diminish that attraction at all.
2006-12-22 05:21:33 · answer #4 · answered by Yacoff 1 · 1⤊ 1⤋
Write the electron configuration for K. It ends with 4s1. To become a K+ ion it has to lose its outermost electron. When you remove the 4s1 electron, the next "outermost" electron is down on level 3, therefore the atom is smaller.
2006-12-22 08:29:04 · answer #5 · answered by The Old Professor 5 · 0⤊ 0⤋
K+ has lost it's the only electron in the outermost electron shell, so it's smaller than K.
2006-12-22 05:18:24 · answer #6 · answered by sep_n 3 · 1⤊ 0⤋
It does, because K+ has a nobel gas configuration, in this case Argon's, and therefore maximum repulsion in its electron cloud causing it to "puff out".
2006-12-22 05:32:25 · answer #7 · answered by Anonymous · 0⤊ 2⤋