3____
√[6] – √[3]
2006-12-22 00:02:01 · 6 answers · asked by styles4u 4 in Science & Mathematics ➔ Mathematics
3____
√[6] – √[3]
=
3(√[6] + √[3]) : (√[6] – √[3])(√[6] + √[3]) =
3√[6] + 3√[3] : 6 - 3=
3√[6] + 3√[3] : 3=
(3√[6] + 3√[3] : 6 - 3=
(3√[6] + 3√[3] : 3= √6 + √3
The answer is: √6 + √3
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2006-12-22 00:13:25 · answer #1 · answered by aeiou 7 · 3⤊ 0⤋
3/(V`6 - V`3)
First: take V`6 - V`3 and change the sign to positive when you multiply it by the top and bottom:
= 3(V`6 + V`3)/(V`6 - V`3)(V`6 + V`3)
= (3V`6 + 3V`3)/(V`36 + V`18 - V`18 - V`9)
Second: find the sqaure root of any radical, if possible and cancel "like" terms:
= (3V`6 + 3V`3)/(6 - 3)
= (3V`6 + 3V`3)/(3)
Third: take both numerators and divide them by -3 and simplify:
= (3V`6)/3 + (3V`3)/3
= V`6 + V`3
2006-12-22 11:48:11 · answer #2 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
3 over (â[6] – â[3]) = 3(â[6] + â[3])) over (6 -3) = â[6] + â[3]
2006-12-22 08:26:49 · answer #3 · answered by James Chan 4 · 1⤊ 0⤋
3____
â[6] – â[3]
multiplying Nr. Dr. by the conjugate
3(â[6] + â[3])
= ----------------------------------
(â[6] – â[3]) (â[6] + â[3])
3( (â[3]â[2]) – â[3])
= ---------------------------
6 - 3
3â[3](â[2]) – 1)
= ---------------------------
3
= â[3](â[2]) – 1)
= root 3 ( root 2 - 1)
2006-12-22 12:35:58 · answer #4 · answered by george t 2 · 0⤊ 0⤋
Divide and multiply the given equation by â[6] + â[3]
ie. [ 3/â[6] – â[3]] / [(â[6] +â[6] – (â[3]+ â[3]))] = 1
2006-12-22 08:31:28 · answer #5 · answered by shasti 3 · 0⤊ 1⤋
The answer is : sqrt6+sqrt3.ok?!!
2006-12-22 10:46:16 · answer #6 · answered by Grasu M 2 · 0⤊ 0⤋