2√[72] + √[32] – 4√[18]
2006-12-22 00:00:32 · 5 answers · asked by styles4u 4 in Science & Mathematics ➔ Mathematics
2√[72] + √[32] – 4√[18] =
2*6√2 + 4√2 – 4*3√2 =
12√2 + 4√2 – 12√2 = 4√2
The answer is 4√2
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2006-12-22 00:47:46 · answer #1 · answered by aeiou 7 · 2⤊ 0⤋
First: simplify each square root: break them down (72, 32, 18)
Second: solve according to order of operations:
2006-12-22 11:50:00 · answer #2 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
The answer is 4*root of 2
2006-12-22 08:37:45 · answer #3 · answered by Nimmi 2 · 0⤊ 0⤋
=2*2*sqrt18+4sqrt2-4sqrt18
=4sqrt2
=4*1.414
=5.6568
2006-12-22 10:44:41 · answer #4 · answered by openpsychy 6 · 0⤊ 0⤋
2sq(72)+sq(32)-4sq(18)
2*sq(9*8) +sq(8*4)-4sq(9*2)
2*sq(3*3*2*2*2)+sq(2*2*2*2*2)-4sq(3*3*2)
2*3*2sq(2)+2*2sq(2)-4*3sq(2)
12sq(2)+4sq(2)-12sq(2)
=4sq(2)
2006-12-22 08:17:41 · answer #5 · answered by sri_july27 2 · 0⤊ 0⤋