Dear,
U joined today. Welcome.... U will surely find u r answers.
Here it is:
void main()
{
int num;
long int factorial;
factorial=1;
printf("\n Enter a number : ");
scanf("%d",&num);
while(num>=1)
{
factorial= factorial * num;
num=num-1;
}
printf("\n The factorial is %ld.",factorial);
}
OM NAMAH SHIVAY
2006-12-22 03:57:45
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answer #1
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answered by Gurudev 3
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#include
int factorial (int n)
{
if (n == 0)
return 1;
else
return (n * factorial (n-1));
}
/* To shorten example, not using argp */
int main ()
{
printf ("%d\n", factorial(3)); // give the required number
return 0;
}
2006-12-22 04:40:21
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answer #2
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answered by TuRbOmAcH 1
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not a nice question to be asked this is a very simple one and u can easily get into it
2006-12-22 04:58:24
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answer #3
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answered by sweetboy 3
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#include
#include
#include
void main()
{
int a,num,fact;
fact=1;
printf("Enter the number");
scanf("%d",&num);
flushall();
system("cls");
for(a=1;a<=num;a++)
fact=fact*a;
printf("The factorial is %d",fact);
getch();
}
2006-12-25 23:56:08
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answer #4
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answered by rocky9281 1
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