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4 answers

As others have said, antilog(0.6021) is the
same as 10^0.6021, if working to base 10.

This comes from the definition of logarithms and
antilogarithms, where, if 10^p = N, then p = log(N).
Taking the antilog of both sides of the latter
equation gives: antilog(p) = antilog[log(N)] = N.
Thus, N = antilog(p) = 10^p

This can easily be done on a calculator, or if you are
online, just type 10^0.6021 into Google and up will come:

10^0.6021 = 4.00036851

2006-12-21 20:16:58 · answer #1 · answered by falzoon 7 · 0 0

Antilogs are the inverse of a log. They are exponentiation. But just as logs can have different bases, the antilog must exponentiate according to the base of the log.

When you say antilog 0.6021, I assume you mean base 10, but it's best to state this explicitly.

antilog(base 10) 0.6021 = 10^(0.6021) = 4.000

to three decimal places.

2006-12-21 19:44:38 · answer #2 · answered by Northstar 7 · 0 0

First, you need to know which base you are using; the most typical are base 10 and base e, e = 2.718...

The log of a number tells you what power to raise the base to to reach that number. For example, log base 10 of 1000 equals 3, since 10 ^ 3 = 1000. Thus, if you want to find the antilog of a number, raise the base to that number for your result. For example, antilog of 4 on base 2 equals 2 ^ 4 = 16. The antilog of 4 on base 10 equals 10 ^ 4 = 10,000.

2006-12-21 19:23:14 · answer #3 · answered by Dan 3 · 0 0

Antilogs are another way of saying "10 to the". Antilogs are just the inverse of logs.

Therefore, if you wanted to calculate the antilog of 0.6021, you would go

10 to the power of 0.6021 [ or 10^(0.6021) ]

2006-12-21 19:09:37 · answer #4 · answered by Puggy 7 · 0 0

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