2006-12-21 16:47:08 · 5 answers · asked by Katrina 1 in Science & Mathematics ➔ Mathematics
x^2 – 4xy + 12ax – 48ay = x(x-4y)+12a(x-4y) = (x-4y)(x+12a).
2006-12-23 10:49:00 · answer #1 · answered by pedazodegente 1 · 2⤊ 0⤋
This type of factoring is known as "grouping". What you would do is take out a common factor from the first two terms, then take a common factor out of the last two terms.
x(x - 4y) + 12a (x - 4y)
Now that you see they these two (complex) terms have the common factor of x - 4y, you now pull out (x - 4y) out of both of them.
(x - 4y) (x + 12a)
2006-12-22 00:52:19 · answer #2 · answered by Puggy 7 · 2⤊ 1⤋
(x-4y)(12a+x)
2006-12-22 02:06:22 · answer #3 · answered by Léon 1 · 3⤊ 0⤋
x(x-4y)+12a(x-4y)
(x-4y)(x+12a)
2006-12-22 18:59:23 · answer #4 · answered by Anonymous · 2⤊ 1⤋
(x+12y)(x-4y)
2006-12-22 01:05:55 · answer #5 · answered by raj 7 · 2⤊ 0⤋