x^3y – 3x^2y – 10xy?

10 ⤊

x^3y – 3x^2y – 10xy?

2006-12-21 16:46:35 · 4 answers · asked by Katrina 1 in Science & Mathematics ➔ Mathematics

4 answers

(x^3)y - 3(x^2)(y) - 10xy

First, factor the biggest term you can out of all three. In this case, it would be xy.

xy [x^2 - 3x - 10]

Now, factor as normal.

xy (x - 5) (x + 2)

2006-12-21 16:50:41 · answer #1 · answered by Puggy 7 · 3⤊ 1⤋

X^3y – 3x^2y – 10xy = xy( x^2- 3x -10) =xy(x+2)(x-5) .

2006-12-22 09:51:16 · answer #2 · answered by locuaz 7 · 2⤊ 0⤋

first factor the common variable out of the three terms
xy(x^2-3x-10)
then factor the quadratic equation
xy(x-5)(x+2)
then nothing else i think

2006-12-21 19:33:28 · answer #3 · answered by arn_14 2 · 3⤊ 0⤋

xy(x^2-3x-10)
xy(x-5)(x+2)

2006-12-22 11:15:47 · answer #4 · answered by Anonymous · 2⤊ 1⤋