2006-12-21 16:42:27 · 7 answers · asked by Katrina 1 in Science & Mathematics ➔ Mathematics
3x^2 – 30x + 48= 0
divide the whole eqn by 3 then u ll hav
x^2 – 10x + 16 =0
now,
8 x 2 = 16 and 8+2=10
so, write it in the form of factors.
x^2 – 8x - 2x+ 16 =0
x(x-8)-2(x-8)=0
(x-8)(x-2)=0
so, x= 2,8
hope it helps u..
2006-12-22 15:44:10 · answer #1 · answered by For peace 3 · 1⤊ 0⤋
If you're trying for solutions to the quadratic equation
3x^2 - 30x +48 = zero
Then the answer is 2 and 8:
3(x^2 - 10x + 16) = 0 Factor the parentheses trinomial:
2(x -2)(x - 8) = 0 etc.
2006-12-21 16:50:35 · answer #2 · answered by answerING 6 · 2⤊ 0⤋
f(x)=3x^2-30x+48
in order for this question to be easier divide it by 3.
x^2-10x+16
then Factor
(x-8) (x-2)
x=8, 2
2006-12-21 16:48:53 · answer #3 · answered by Rakiztah 2 · 2⤊ 0⤋
3x² – 30x + 48
= 3(x² - 10x +16)
= 3(x - 8)(x - 2)
2006-12-21 16:44:36 · answer #4 · answered by Wal C 6 · 2⤊ 0⤋
Divide everything in the equation by 3:
x^2 - 10x + 16
Then factor:
(x -8)(x - 2)
x = 8, 2
2006-12-21 16:46:01 · answer #5 · answered by Joy M 7 · 2⤊ 0⤋
(3x-24)(x-2)
=>3(x-8)(x-2)
2006-12-21 17:09:00 · answer #6 · answered by raj 7 · 2⤊ 0⤋
(3x-6)(x-8)
3x-6=0
x-8=0
x=2 and 8
2006-12-22 11:22:30 · answer #7 · answered by Anonymous · 2⤊ 0⤋