In a 10' x 15' room that's 8' high calculate the distance from the lower left to the upper right.

Question

Hint: It would take two pythagoreans to answer this equation.

Please tell how you got your answer.

Answer 1

Repeated use of the Pythagorean theorem.

10'x15' rectangular floor means the hypoteneuse across the floor is sqrt(10^2+15^2) =sqrt(325). Then the line across the rectangle with the height forms a new triangle, and its hyptoneuse (across the room as you describe) is sqrt(8^2 + sqrt(325)^2) = sqrt(64+ 325) = sqrt(389) = about 19.72308292

Answer 2

Now if you mean the from the floor of the left corner of the room to the ceiling of the right corner then it will take two calculations using Pythagorean theorem.

first 10^2 + 15^2 = 325
sqr(325) = 18 rounded

next 18^2 + 8^2 = 388
sqr(388) = 19.7 rounded

Answer 3

19.72

First, draw a diagram. The distance from the lower lefthand corner to the lower righthand corner is 18.03 by the Pythagorean theorem sqrt (10^2 + 15^2). Using this result, the distance you want is found by sqrt (8^2 + 18.03^2)= 19.72

Answer 4

i don't understand this "lower left to upper right" part however if you're talking about the diagonal of the room ,the answer is
root of length sq. + breadth sq. +height sq.
=root of 100+225+64
=root of 389 sq. units???

Answer 5

it will be the iagonal
rt(a^2+b^2+c^2)
=rt(10^2+15^2+8^2)
rt(100+225+64)
rt(389)
=19.72 sq.ft

Answer 6

The answer is easy enough to figure out. If the objective it to have people jump though hoops, you have done that.

Answer 7

19.7