How do I calculate the tension in a rope lifting a 3.8 kg bucket at a constant speed?

Question

Thanks for serious answers only. I am trying to learn.

Answer 1

tension = (3.8 kg)(9.8 m/s^2) = 37.24 N

Answer 2

Because the bucket is being lifted at a constant speed, all of the forces are in equilibrium. If friction is negligible, than there are two forces acting on the bucket. They are the gravity pulling the bucket down and the tension force acting opposite the gravity. These forces are at equilibrium, therefore they should be equal in size. This allows us to calculate the weight of the bucket. The weight is a force that will equal the tension. The weight, or the force due to gravity (Fg), is equal to the mass of the bucket multiplied by the acceleration due to gravity(g). g = 9.81m/s^2.
Fg = (9.81)(3.8kg), Fg = 37.278 N. The weight equals 37.278 newtons, so the tension will equal 37.278 but will act in the opposite direction

Answer 3

Force = mass X acceleration.

The only acceleration is gravity. The constant velocity adds nothing.

Therefore;
Force = 3.8 kg X 9.8 meters/s/s = 37.24 newtons