a. 2NaCI+H2SO4+ ---->HCL+NaSO4
b. NH3+H2O----->2NH4OH
c. KOH+H2SO4------>KHSO4+H2O
d. 2Na+S ------>2NaS
2006-12-21 13:59:30 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
C.
a is wrong because there is insufficient Sodium written.
b is not correct because there is a 2 in front which would imbalance the whole equation.
d is also not correct because there is only one sulphur but there is 2 in the end.
c is correct because all the elements are in the right proportion,
2006-12-21 14:02:58 · answer #1 · answered by PIPI B 4 · 0⤊ 1⤋
C
D does not have four potassium atoms . . . the 4 is in SO4 alone.
Also, if D were balanced correctly it would be Na(2)S, indicating two Na atoms with one S atom because sodium has a charge of +1 and Sulfur has a charge of -2.
2006-12-21 14:28:11 · answer #2 · answered by Lisa 2 · 0⤊ 0⤋
It is D!!! C is not balanced because on the right there are 4 K and on the left there are 1 so therefore, that one is wrong.
2006-12-21 14:09:46 · answer #3 · answered by Amba 2 · 0⤊ 0⤋
C is balanced with equal number of elements .
2006-12-21 19:31:42 · answer #4 · answered by Pocket Rocket 2 · 0⤊ 0⤋
d
2006-12-21 14:02:51 · answer #5 · answered by Anonymous · 0⤊ 0⤋
c
2006-12-21 14:01:51 · answer #6 · answered by Anonymous · 0⤊ 0⤋
"C" is the only balanced equation.
2006-12-21 14:01:56 · answer #7 · answered by Anonymous · 0⤊ 0⤋
C
2006-12-21 14:15:29 · answer #8 · answered by Anonymous · 0⤊ 0⤋
C
2006-12-21 14:04:37 · answer #9 · answered by crabshacks 2 · 0⤊ 0⤋