Determine three values of x such that x^2=2x.?

Question

two are 2 and 4, but I cant get the third

Answer 1

x^2 = 2x
Subtract 2x from both sides.
x^2 - 2x = 0
Factorise.
x(x - 2) = 0
Therefore, x = 0 or x = 2.
These are the only two solutions.

Answer 2

evaluate putting the 1st 2 equivalent to a minimum of one yet another: xy = x/y xy^2 = x (multiply the two sides through y) xy^2 - x = 0 (subtract x from the two sides) x (y^2 - a million) = 0 (element the left factor) x = 0, y^2 -a million = 0 (set each element equivalent to 0) x = 0 y^2 = a million y = -a million or a million So we are given 3 conceivable strategies...the case the place x = 0, y=a million, and y=-a million. Now plug those into all 3 equations, one after the different, and notice what makes them equivalent (x=0) xy = x/y = x-y 0y = 0/y = 0-y 0 = 0 = -y y = 0...yet this would make the x/y undefined, so x=0 isn't a answer. (y=a million) x(a million) = x/a million = x-a million x = x = x-a million 0 = 0 = -a million (Subtract x from the two sides...yet this yields no answer.) (y=-a million) x(-a million) = x/-a million = x-(-a million) -x = -x = x + a million So x+a million = -x 2x + a million = 0 2x = -a million x = -a million/2 (And this gives a answer.) to that end, the only values which make this genuine are (x = -a million/2,y = -a million), which makes xy = x/y = x-y = (a million/2)

Answer 3

x^2=2x

is equal to

x^2-2X+0 expression

It is a quadratic equation. Thus there will be only 2 values of X mathematically. Now why not try '0'. If you put 0 for x it satisfies and might become the value of x as asekd in the question

Now one question: does x=4 satisfies the equation? certainly no. so the equation will have only two values: 0 and 2

Thus the second correct value of x satisfying the equation is 0
:)

Answer 4

x^2 = 2x

First: set this equation to equal "0" > subtract 2x from both sids:

x^2 - 2x = 2x - 2x
x^2 -2x = 0

Second: factor > find the least common factor which is "x" >

x(x - 2) = 0

Third: solve for each "x" by setting them to equal zero:

1. x = 0

2. x - 2 = 0
x - 2 = 0 + 2
x = 2

x = 0, 2

Answer 5

x^2 = 2x
x^2 - 2x = 0
x (x - 2) = 0
therefore,
x =0 and x = 2
since we have the greatest power to be 2 we will have only two values for the given equation.....so the values are 2,0....
4 is not one of the value of above equation...

Answer 6

x^2=2x
x^2-2x = 0
x(x - 2) = 0
x = 0 or x - 2 = 0
x = 0 or x =2

Answer 7

x^2=2x
x^2-2x=0
x(x-2) = 0
x =0 or 2

4 is surely not the answer.
let us check, if 4 is the answer,

L.H.S = x^2 = 16
R.H.S = 2x = 8

L.H.S is not equal to R.H.S
Therefore 4 is not the answer.
There is only 2 answers. 0 and 2

Answer 8

x^2=2x
x^2-2x=0
x(x-2)=0
x=0 or 2
for a second degree equation there can be only two solutions

Answer 9

x^2= 2x
x^2-2x = 0
x(x-2)=0
So x = 0 or 2
NOT 4

Answer 10

I am not sure what the ^ sign is but:

2(4)(2)-16

2(8)=16

so

2(4)(2)=2(8)