2006-12-21 10:49:45 · 8 answers · asked by kiki d 1 in Science & Mathematics ➔ Mathematics
3x^2-8x-35=0
product =-105 sum=-8
the middle term can be split as -15 and +7
3x^2-15x+7x-35=0
(3x+7)(x-5)=0
x=-7/3 or 5
2006-12-21 11:06:18 · answer #1 · answered by raj 7 · 1⤊ 0⤋
OK!
3x^2-8x = 35
3x^2-8x -35 =0
This is a simple quadratic equation. Use the quadratric formula, plug and chug! http://en.wikipedia.org/wiki/Quadratic_formula
.
2006-12-21 10:52:37 · answer #2 · answered by Jerry P 6 · 2⤊ 0⤋
3(x)(x) - 8x = 35
3x² - 8x = 35
3x² - 8x - 35 = 35 - 35
3x² - 8x - 35 = 0
3x² - 15x + 7x - 35
3x(x - 5) + 7(x - 5)
(3x + 7)(x - 5)
- - - - - - -s-
2006-12-21 11:14:55 · answer #3 · answered by SAMUEL D 7 · 1⤊ 0⤋
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2016-12-18 17:25:10 · answer #4 · answered by Anonymous · 0⤊ 0⤋
3x^2-8x=35
3x^2-8x-35=0
(3x+7)(x-5)=0
3x+7=0
x=-7/3
x-5=0
x=5
x=5, -7/3
2006-12-21 13:15:49 · answer #5 · answered by mu_do_in 3 · 1⤊ 0⤋
3x^2-8x-35=0
(3x+7)(x-5)=0
3x+7=0
x-5=0
x=-7/3 and 5
2006-12-21 11:02:16 · answer #6 · answered by Anonymous · 1⤊ 0⤋
You could also factor.
(3x + 7)(x - 5)
then you get -7/3 and 5 for the answers!
2006-12-21 10:59:51 · answer #7 · answered by christmastree 3 · 2⤊ 0⤋
3x^2-8x-35=0
3x^2-15x+7x-35=0
3x(x-5)+7(x-5)=0
(3x+7)(x-5)=0
x=-7/3,5
2006-12-21 11:37:58 · answer #8 · answered by Anonymous · 1⤊ 0⤋