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4 2/3 + 2 3/5

2006-12-21 08:14:21 · 10 answers · asked by electra 1 in Science & Mathematics Mathematics

10 answers

Sum the integers and after, sum the fractions.
Thus,
(4 + 2) + (2/3 + 3/5) =
LCF(3, 5) = 15
6 + (10/15) + 9/15) =
6 + 19/15 = 6 19/15 or 109/15
::

2006-12-21 09:15:27 · answer #1 · answered by aeiou 7 · 2 0

4 2/3 + 2 3/5 = 4+2 + 2/3 + 3/5
= 6 + 2/3 + 3/5
= 6 + (2*5)/(3*5) + (3*3)/(5*3)
= 6 + 10/15 + 9/15
= 6 + 19/15
= 6 + 15/15 + 4/15
= 6 + 1 + 4/15
= 7 4/15

2006-12-21 16:18:17 · answer #2 · answered by Math geek 3 · 0 0

multiply the number outside the fraction by the denominator and add the numerator

4 2/3 = 4*3 +2 all over 3 = 14/3
2 3/5 = 2*5 + 3 all over 5 = 13/5

find a number that both denominators will divide into evenly

3 and 5 go into 15 evenly

divide the denominator into that number and multiply the quotent by the numerator

3 divides into 15 5 times. 5 * 14 = 70 so 14/3 = 70/15
5 divides into 15 3 times. 3 * 13 = 39 so 13/5 = 39/15

70/15 + 39/15 = 109/15

15 goes into 109 7 times withh 4 left over so 109/15 = 7 4/15

hope this helped.

2006-12-21 16:24:07 · answer #3 · answered by Anonymous · 0 0

7 4/15

4 2/3 =14/3=70/15

2 3/5 =13/5=39/15

70/15+39/15=109/15

2006-12-21 16:19:49 · answer #4 · answered by Steve H 5 · 0 0

7 4/15

2006-12-21 16:18:08 · answer #5 · answered by mtzbarba 1 · 0 0

4+2 and 2/3 + 3/5
6 19/15
7 4/15

2006-12-21 16:19:17 · answer #6 · answered by      7 · 0 0

it = 109/15 which is 7 4/15

2006-12-21 16:24:26 · answer #7 · answered by blue ocean 1 · 0 0

Feel free to IM me. I'm online right now and I have a degree in secondary math education. I'll be happy to give you some online tutoring.

2006-12-21 16:23:40 · answer #8 · answered by iuneedscoachknight 4 · 0 0

The pattern is the going to be the same format...take a look at the previous problems we've helped you with :-)

2006-12-21 16:22:03 · answer #9 · answered by ♪♥Annie♥♪ 6 · 0 0

You aint going to see any pattern because you are making these people do your HOME WORK

2006-12-21 16:19:42 · answer #10 · answered by Rutul 3 · 1 0

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