It takes at least 13.6 eV of energy to ionize a hydrogen atom. How much energy is in this units of kJ/mol?

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It takes at least 13.6 eV of energy to ionize a hydrogen atom. How much energy is in this units of kJ/mol?

Given information.
1 eV = 1.602 x 10 raised to the -19th power J
1 J = 1 kg m-squared over s-squared

2006-12-21 07:55:08 · 4 answers · asked by Anitec 2 in Science & Mathematics ➔ Chemistry

Please show appropriate work.

2006-12-21 07:55:33 · update #1

4 answers

13.6 eV=(13.6eV* 1.602x10^-19J/eV)= 2.178x10^-18J per photon
Multiply by Avogadro's number 6.02x10^23 go get 1.312x10^5 J/mol
Divide by 1000 to get: 1312 kJ/mol

2006-12-21 08:01:31 · answer #1 · answered by Peter B 3 · 0⤊ 0⤋

1 mol of H atom has 6.023 x 10^23 atoms
1 ev = 1.6 x 10^(-19) J
solving
3.6 KJ

2006-12-21 16:01:12 · answer #2 · answered by bh 2 · 0⤊ 0⤋

13.6ev*1.602*10^-19j*1kj*6.022*10^23/1ev/1000j/1mol

2006-12-21 16:10:32 · answer #3 · answered by Anonymous · 0⤊ 0⤋

3.06

2006-12-21 15:59:12 · answer #4 · answered by Anonymous · 0⤊ 0⤋