How do I find distance from acceleration and time?

Question

I need to know that, and a couple other answers to questions like finding time from acceleration and distance, and other things. Thanks.

Answer 1

Compute how long it takes you.

Answer 2

You cannot find distance from only acceleration and time. You also need either the initial velocity or the final velocity. If you have the final velocity then use the formula: d = vi t + 1/2 a t^2
If you have the final velocity then: d = vf - 1/2 a t^2.
If either vi or vf is 0 then sub in 0 to one of those formulas.

But you definetly cannot determine distance with only acceleration and time. That would make no physical sense and there would be an infinity of solutions.

Answer 3

For motion problems you use the following equations

(1) distance = average velocity * time or d =vt

(2) average velocity = (final velocity + initial velocity)/2 or v = (vf+vi)/2

Combining (1) and (2)

(3) d = (vf+vi)t / 2


(4) acceleration = (final velocity - initial velocity)/time or a = (vf-vi)/t

If we combine (3) and (4) and eliminate vf:

(5) d = vi t + 1/2 at^2

If we combine (3) and (4) and eliminate t:

(6) 2ad = vf^2 - vi^2

So you have 6 equations. All you have to do is choose the equation which will fit the given in the problem.

Answer 4

Distance= Time x Speed
Acceleration= Force/Mass
Time= Distance/Speed

Answer 5

Use these two formulas:

v = at + v0
d = 0.5at² + v0t + d0

v0 and d0 are the initial velocity and distance.

To find distance from acceleration and time, just use the second formula.
To find time from acceleration and distance, use the second formula again, but solve it for t.

Answer 6

S=ut+1/2(at^2)
where S= distance
U= initial velocity
t= time
a= accelaration

Answer 7

Assuming constant acceleration: distance traveled is directly proportional to the square of the time.

(You do realize that the web is full of physics pages, right?)

One of those pages now...

Answer 8

speed is the fee of replace of distance with time, or in different words, it particularly is the DIFFERENTIAL of distance: ds / dt = v. in addition, acceleration is the fee of replace of speed with time, so it particularly is the DIFFERENTIAL of speed: dv / dt = a. Reversing the approach, speed is the vital of acceleration and distance is the vital of speed.

Answer 9

Use da formula :

s = ut +1/2at^2

where s = distance
u = initial speed

Answer 10

we know d^2s/dt^2 =a. Hence by integrating two times we can find acceleration

Answer 11

It's a problem to sort out all these responses, so I thought I'd point out a couple of errors above:
In bh's 4th line, V² = (u +√(2as))²

In dax's (6), 2ad = (Vf -Vi)²