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E = mc2 does not describe the value of "c" for what it is, but what it does - like the current equation for the force of gravity. But, when the value of "c" is equal to that of "h" in form of energy, then the equation for a gravitational field "c2 = E/m" makes sense, right?

2006-12-21 06:46:06 · 7 answers · asked by Anonymous in Science & Mathematics Physics

7 answers

I'm confused by your question. "c" and "h" are two distinct constants. They can't be equal.

2006-12-21 06:55:07 · answer #1 · answered by Steph. 3 · 1 0

c^2 = E/m is one way to define the speed of light. A more common way is to say c = E/B where E is the electric field and B is the magnetic field. As far as c = h, they are two distinct constants with different units. So they can never be equal. When you multiply the two you do get a useful constant, 1240 eV nm, but they are by no means equal.

2006-12-22 01:03:13 · answer #2 · answered by thegreatdilberto 2 · 0 0

You don't need to have the value of c equal the value of h to rearrange the equation E=mc2 to become c2=E/m, that is just algebra; just divide both sides by m.

2006-12-21 15:50:40 · answer #3 · answered by campbelp2002 7 · 0 0

"c" is the speed of light in that formula, but if you mean the Planck's constant by "h", you should notice that these tow does not have the same dimensions, i.e. "c" is a [length]/[time] while "h" is a [mass]*[length]*[length]/[time]. So these quantities must have differrent units and their numerical values DEPEND on the units we chose. That means means if their values equal in SI units, they will certainly not in other units like Brithis, or an arbitrary one. This means that an equality for quantities with different units does not have any meaning.

2006-12-21 15:45:35 · answer #4 · answered by Farshad 2 · 0 0

E=mc2 is energy equals mass x speed of light x speed of light. A basic formula for nuclear energy...h is a different critter.

2006-12-21 14:57:58 · answer #5 · answered by Anonymous · 0 0

No

2006-12-21 14:56:08 · answer #6 · answered by Gene 7 · 0 0

Um, not so much..

2006-12-21 14:53:23 · answer #7 · answered by Anonymous · 0 0

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