How many litres of solutions A and B should be mixed to make 100 litres of 14% syrup
2006-12-21 05:31:37 · 3 answers · asked by KIMBA 1 in Science & Mathematics ➔ Chemistry
prove by mathematical induction
2006-12-21 05:44:35 · update #1
.05 * volume how much syrup in solution A per volume.
.2 * volume how much syrup in solution B per volume.
X = volume of syrup A
Y = volume of syrup B
X + Y =100
.05 * X + .2 * Y = .14 * 100
System of equations ... 2 equations in 2 unknowns.
Since from the first equation Y = 100 - X
Plug that into the second equation and solve for X, and
then back-plug and solve for Y.
2006-12-21 05:41:14 · answer #1 · answered by themountainviewguy 4 · 0⤊ 0⤋
First start with x liters (L) of solution A. Then the amount of liters of B must be 100 - x since A and B combined have to equal 100.
So .05 * x + .20 * (100 - x) = .14 * 100L, and if you solve for x you'll find out x = 40L.
So you need 40 liters A and 60 liters B.
2006-12-21 13:41:21 · answer #2 · answered by EcoJock 2 · 1⤊ 0⤋
OK!
A*(0.05) + B*(0.20) = 100*(0.14)
and
A + B = 100
Two equations in two variables, plug and chug!
2006-12-21 13:35:58 · answer #3 · answered by Jerry P 6 · 1⤊ 0⤋