A. f (x) = x + 3
B. f (x) = 5x + 3
C. f (x) = 3x + 5
D. f (x) = 3
2006-12-21 04:08:59 · 7 answers · asked by rmfurther3000 1 in Science & Mathematics ➔ Mathematics
C. f(x) = 3x+5
f'(x)= 3 .
2006-12-21 04:13:14 · answer #1 · answered by Anonymous · 4⤊ 0⤋
Apply the power law to each equation. Only one works out to 3. (that's c)
d/dx c*x^n = n*c*x^(n-1)
In the first, x=x^1 and 3 is a constant (a constant stays constant, so it's rate of change is always 0). The derivative is 1*x^0 +0 = 1. (Anything to the zeroth power equals 1)
In the second, the derivative of 5x^1 + 3 = 1*5*x^0 + 0 = 5
etc.
2006-12-21 05:01:38 · answer #2 · answered by Bob G 6 · 0⤊ 0⤋
The answer is C. 3x + 5. The most general
answer is 3x + C, where C is a constant
2006-12-21 04:39:03 · answer #3 · answered by steiner1745 7 · 0⤊ 0⤋
The Answer is C. f (x) =3x + 5
2006-12-21 04:27:57 · answer #4 · answered by ATS 2 · 0⤊ 0⤋
The answer is C f(x) = 3x-5 : its derivative is always 3
The derivative of A is always 1
The derivative of B is always 5
The derivative of Dis always 0
2006-12-21 04:14:37 · answer #5 · answered by ironduke8159 7 · 1⤊ 0⤋
C.
A. = 1, B. = 5, C. = 3, D. = 0
2006-12-21 04:10:37 · answer #6 · answered by Anonymous · 0⤊ 0⤋
c.
2006-12-21 04:11:36 · answer #7 · answered by openpsychy 6 · 0⤊ 0⤋