2006-12-21 02:24:47 · 8 answers · asked by wicked 1 in Science & Mathematics ➔ Mathematics
The sinuse law :a/sinA=c/sinC, but a=5,A=13*, C=180*-(A+B)=143*, (* is degrees).you has: 5/sin13*=c/sin143*, then c=5sin143*/sin13*=5x0.6/0.225=3/0.225=3000/225=13and1/3=13.333333.......END!
2006-12-21 02:48:59 · answer #1 · answered by grassu a 3 · 0⤊ 0⤋
a=5 ; A = 13 degrees ; B = 24 degrees
C = 180 -13 - 24 = 143degrees
a/sinA = c/sinC
c=a* sinC/sinA
=5* sin143/sin13 = 13.377
2006-12-21 13:12:43 · answer #2 · answered by ATS 2 · 0⤊ 0⤋
A=13deg
B=24deg
C=143deg
[A+B+C=180]
We have the rule of Sines
a/sinA=b/sinB=c/sinC
c=a*sinC/sinA
=5*sin143/sin13
[sin[180-z]=sinz]
=5*sin37/sin13
=5*.6018/.225
=13.37
2006-12-21 12:54:25 · answer #3 · answered by openpsychy 6 · 0⤊ 0⤋
You can't find the answer using trigonometry because it must be a right traingle, if C=90degrees, then 90+13+24 wouldn't equal 180, so it couldn't be a right triangle.
2006-12-21 10:31:20 · answer #4 · answered by nightshadyraytiprocshadow 2 · 0⤊ 1⤋
a/sinA=b/sinB=c/sinC
angle C=180-(13+24)=143
5/sin13=c/sin143
c=5sin143/sin13
or use trig table to find c
2006-12-21 10:58:02 · answer #5 · answered by iyiogrenci 6 · 0⤊ 0⤋
I'm assuming a = 5, is the side opposite A = 13 degrees.
C = 180 - A - B = 143
a sin(B) = b sin(A)
b = a sin(B)/sin(A)
c = a cos(B) + b cos(A)
2006-12-21 10:32:07 · answer #6 · answered by feanor 7 · 0⤊ 0⤋
Come on.... looks like you have posted all of your homework problems here. You need to do this yourself.
Use the same formulas I left you on the other one.
Sure.. you prob. have a GREAT reason why... but it is still YOUR homework and you know it.
2006-12-21 10:40:06 · answer #7 · answered by ca_surveyor 7 · 0⤊ 0⤋
i think its 143 or sumthin.....
2006-12-21 10:27:54 · answer #8 · answered by Anonymous · 0⤊ 1⤋