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B= 30 degrees, C=43 degrees and a=8

2006-12-21 02:22:52 · 4 answers · asked by wicked 1 in Science & Mathematics Mathematics

4 answers

Angle A = 180 - 30 -43
= 107 degrees

Sine rule: b/Sin B = a/Sin A
b = 4.175 units

Sine rule: c/Sin C = a/Sin A
c = 5.71 units

Area of triangle = 1/2 x 5.71 x 8 x sin30
= 11.42 units^2

Basically that's all. I do not think there is anything else.

2006-12-21 03:07:02 · answer #1 · answered by PIPI B 4 · 1 0

OK...

Angle A is easy 180 -(30+43) = 107

proportion the others:

8/107 = b/30 = 2.24

8/107 c/43 = 3.21

now go do the rest of your homework yourself .

2006-12-21 10:37:44 · answer #2 · answered by ca_surveyor 7 · 0 2

we have the sine rule
a/sinA=b/sinb=c/sinC
B=30deg
C=43deg
A=107deg
[A+B+C=180]
b=a/sinA*sinB
=8*sin107/sin30
=8*sin73/sin30
[sin[180-z]=sinz]
=8*.9563/.5
=15.3
c=8*sinC/sinA
=8*sin43/sin73
=8*.6819/.9563
=5.704
all the sides and angles are known.
hence the triangle is solved.

2006-12-21 13:06:46 · answer #3 · answered by openpsychy 6 · 0 0

You can sin rule.

2006-12-21 11:25:40 · answer #4 · answered by aminnyus 2 · 0 0

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