-8=x^3
2006-12-21 01:57:03 · 9 answers · asked by s a 2 in Science & Mathematics ➔ Mathematics
-8=x^3
(-2)^3=x^3
Therefore -2=x
2006-12-21 02:01:48 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
x=-8^1/3
=-2
2006-12-21 10:22:23 · answer #2 · answered by ships 2 · 0⤊ 0⤋
x = -2
2006-12-21 10:16:08 · answer #3 · answered by ~ ANGEL ~ 5 · 0⤊ 0⤋
x= -2
2006-12-21 09:58:51 · answer #4 · answered by Nikko 2 · 0⤊ 0⤋
x= -2
(-2)^3=-8
2006-12-21 09:59:12 · answer #5 · answered by physics 2 · 0⤊ 0⤋
Ok, first off, intergers: Multiplying by two positives or two negatives gives you a positive. If the signs are opposite, the result is negative.
Now, think of -8 as 8. What's two times two?
Four. Now, multiply by two again and you get eight.
Multiply -2 by -2 and you get 4; multiply 4 by -2 and you get -8.
So, x is equal to -2.
2006-12-21 11:50:43 · answer #6 · answered by ZZ 4 · 0⤊ 0⤋
(x^3+8)=0 <=> (x+2)(x^2-2x+4)=0 then x+2=0 or x^2-2x+4=0.
if x+2=0 then x=-2 and if x^2-2x+4=0 then (x+1)^2+3=0 =>x+1=+/-isqrt3 => x=-1+/-isqrt3.the solutins is {-2,-1+/-isqrt3}. END!
2006-12-21 10:06:59 · answer #7 · answered by grassu a 3 · 1⤊ 0⤋
take the cube root of both sides of the equation.
x = -2
2006-12-21 10:24:35 · answer #8 · answered by Ray 5 · 0⤊ 0⤋
I assume you mean "solve".
x^3 = (x)(x)(x) = -8
(-2)(-2)(-2) = -8
x= -2
2006-12-21 09:59:19 · answer #9 · answered by TimmyD 3 · 0⤊ 0⤋