How does the original equilibrium respond to the following stress? Explain and Discuss.?

Question

Original equilibrium: Fe^(3+) + SCN^(1-) <-----> Fe(SCN)^(2+)

1. Add Fe(NO3)3

2. Add KSCN

3. Add AgNO3

4. Add NaOH

Answer 1

Items 1. and 2. both add reactants on the left increasing their concentration. This will drive the equilibrium to the right.

Items 3. and 4. add additional reactants which will react with the reactants on the left causing their concentrations to decrease. This will drive the equilibrium to the left.

AgNO3 (aq) + SCN^(-1) (aq) ---> AgSCN (s) + NO3^(-1) (aq)

NaOH (aq) + Fe^(3+) (aq) ---> Na^(+1) (aq) + Fe(OH)3 (s)

Answer 2

a- will shift to the left it is going to accomplish that as there are going to extra molecules on the RHS (7 + 4 =11) yet on the LHS there is in basic terms 10 (4 + 6 = 10). because of the fact the quantity decreases they reaction will regulate as to have much less molecules interior the reaction vessel. STEVEGEO- hi, might it not bypass the left as there may be much less molecules? might it not have the comparable result with the comparable as increasing the stress? A shrink in quantity works to the main appropriate interior the Haber technique (N2 + 3H2 --> 2NH3) as there are going to be much less molecules present?? thank you Trevor!