How are M&Ms made?
If you had an infinite supply of water and a 5 quart and 3 quart pail, how would you measure exactly 4 quarts?
You have 8 balls. One of them is weighs less than others. You have a balance to measure balls against each other. What is the least number of times you can use the scale to find the ball that weighs less?
2006-12-19 20:22:21 · 4 answers · asked by Hanna S 1 in Education & Reference ➔ Trivia
1. M&Ms--no idea
2. You fill the 5 quart pail dump the water into the 3 quart one. You should have 2 quarts left in the 5 quart one. You dump the 3 quart pail so that it's empty again, then put the 2 quarts left in the 5 quart pail into the 3 quart one. Then, you fill the 5 quart pail again, and empty it into the 3 quart one so that it's full. Since 5 minus 1 equals 4, then you have 4 quarts!!
3. 3 times, because you divide 8 by 2 and you have 4. Put them on the scale and the side that the lighter ball is on, it will rise. So then, put 4 on the scale (2 on each side), one will rise, and you know that is on that side. When you get to the final 2, the side that rises, is you ball.
2006-12-20 08:03:31 · answer #1 · answered by Cutebruce88 2 · 1⤊ 0⤋
1. In a factory. I think they mold the chocolate then coat it in a rotating drum.
2. Fill the 3 quart pail and pour it into the 5 quart pail. Fill the 3 quart pail again and pour into the 5 quart pail just until the 5 quart is full. Empty out the 5 quart pail; pour the remaining 1 quart from the 3q pail to the 5q pail. Then fill the 3 quart pail one more time and add it to the 5q pail to make exactly 4 quarts.
3. Three times. First weigh 4 against 4; then out of the lighter 4 weigh 2 against 2; then out of the lighter 2 weigh 1 against 1 to find the light ball.
2006-12-21 15:31:35 · answer #2 · answered by Robin 4 · 0⤊ 0⤋
Take an empty 5 quart container and and pore the 3 quarts in, then pour from the 5 quart container into the one with 3 quarts until each had the same amount .
If you placed 4 ball on each side of the scale, one side would be heaver. so you would have 1 in 4 you would use the scale 4 times.
2006-12-21 14:56:59 · answer #3 · answered by Anonymous · 0⤊ 0⤋
I like Robin's answer to #1 and #2
EDITTING
IN #3 ITS ONLY TWICE
Put three balls on each side. if they Balance, wiegh the other two balls. If they do not balance, take the three balls on the lighter side. weigh two of them. if they balance the other ball is the light one.
2006-12-21 23:16:46 · answer #4 · answered by free2bme55 3 · 0⤊ 0⤋