What is the next number?
2006-12-19 18:54:53 · 9 answers · asked by hamed 1 in Science & Mathematics ➔ Mathematics
807
how???
frm 8559 - 4472 = 4087
frm 4472 - 1888 = 2584
pattern for the difference bet each sequence is the cuurent difference minus minus the difference b4 this
meaning the current difference is bet 4472 and 1888 = 2584 minus difference for two number b4 the sequence is 4087.
so it'll become 2584-4987 = 1081.
so the answer is 1888 - 1081= 807.
2006-12-19 19:23:41 · answer #1 · answered by syikin_310 2 · 1⤊ 0⤋
8559 - 4472 = 4087 and 4472 - 1888 = 2584
pattern for the difference bet each sequence is the cuurent difference minus minus the difference.
Answer is 1888 - 1081= 807.
2006-12-19 19:27:02 · answer #2 · answered by Kinu Sharma 2 · 1⤊ 0⤋
want to know the next number? u must know the difference between 8559 and 4472.
first u must do 8559-4472 = ?
4472 - 1888 = ?
then, u can know what the next number by comparng the two answer that u get ..then, u will know what to do.
gud luck
2006-12-19 19:02:05 · answer #3 · answered by miss_ooO 2 · 0⤊ 2⤋
807
2006-12-19 21:56:05 · answer #4 · answered by AndyPandy 3 · 1⤊ 0⤋
If the series is generated by a 2nd degree polynomial, the next number is 807
2006-12-19 19:45:41 · answer #5 · answered by Helmut 7 · 0⤊ 1⤋
807 if the series was calculated with the polynomial 751.5x^2 -6341.5x+14149.
807 adjusting a first order polynomial to the differences of the series.
807 if you pick a random number. =P
2006-12-19 19:14:40 · answer #6 · answered by andrade4sveta 2 · 0⤊ 0⤋
i don't know the answer but thanks for two points
u would never get the answer of it because 8559-4472=4087
and 4472-1888= 3584
u a just giving an equation
2006-12-19 19:24:44 · answer #7 · answered by malli 1 · 0⤊ 1⤋
One possible answer is 807. This is going off the pattern suggested by the user above me.
It is possible that there are other patterns, just less obvious.
2006-12-19 19:08:20 · answer #8 · answered by pinkpearls 3 · 0⤊ 0⤋
I think it is 807
2006-12-19 22:16:36 · answer #9 · answered by Srinivas c 2 · 1⤊ 0⤋