because person want 2 give back yr force 2 inverse direction and 2 achive dis goal he should fall
2006-12-19 18:47:28
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answer #1
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answered by celever 2
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The force applied to the pushed person, is equal to the pusher. The pusher also creates a force (reaction force) with the earth in the opposite direction with the use of friction, the pushed person does not (or not of the same magnitude).
However, if they were on a frictionless surface. They would both fall.
2006-12-20 03:36:35
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answer #2
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answered by blue_fenetre 2
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The forces are equal, however, the balance is different. For example, if you were pushing a large man, you'd be the first one to fall over.
When you push, you brace yourself against it, (lean forward), and thus when the you are pushed backwards with the force of your own push, you don't lose your balance. However, if the person you were pushing would suddenly disappear you'd fall forwards.
2006-12-20 02:47:49
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answer #3
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answered by dane 4
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For every action, there is an equal and opposite reaction. Action: you push. Equal and Opposite Reaction: your friend falls over. You don't fall over because your mass is at rest, and is staying at rest due to the fact you are bracing yourself when you push. If you could not push your friend over (insufficient force, excessively massive friend, insufficient bracing, etc.) you could fall over.
2006-12-20 02:49:23
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answer #4
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answered by Anonymous
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Gee that's tough one. If you push some one and who ever pushes him...he will fall and hit the ground assuming you pud him hard enough and not just tap him on the shoulder.
By the way....did you have to mentions 3rd law twice?
2006-12-20 03:05:08
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answer #5
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answered by iraq51 7
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