e has it's own little set of rules.
If y = e^x
dy/dx = e^x.
2006-12-19 21:08:16
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answer #1
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answered by Brenmore 5
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If the x has a coefficient in front of it, you would still have to multiply e by that coefficient.
So dy/dx of e^3x = 3e^3x.
2006-12-19 20:05:28
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answer #2
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answered by Snerler 3
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If going to say this too. The derivative of e^x is e^x. That's one of the reasons why e is such a special number. Just so you'd like to know, the derivative of log base e of x is 1/x. Have fun with your maths.
2006-12-19 18:10:29
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answer #3
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answered by iamdaroot 2
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I agree with the previous answers... anyways, be careful later, when e is raised to a power that is more than an x. even thou derivative of e^x is e^x, it's not the case when it goes e^(2x) or anything other than x...
2006-12-19 18:18:07
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answer #4
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answered by Kohaku 2
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I always thought that the Euhler function was unique in it being the derivative of itself. (Sorry, I know not the answer but the others surprised me.)
2006-12-19 18:28:42
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answer #5
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answered by antoinebucher 1
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y = e^x
dy/dx = e^x
2006-12-19 19:41:05
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answer #6
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answered by george t 2
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how many ever times u do derivative to this,u get e^x only..its a special case..
2006-12-19 18:32:05
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answer #7
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answered by For peace 3
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The derivative of e^x is just itself, e^x.
2006-12-19 18:07:15
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answer #8
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answered by Doug 2
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If y = e^x
dy/dx = e^x also.
2006-12-19 18:07:32
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answer #9
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answered by Northstar 7
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it will always the same...
Se^x = e^x
y = e^x
y' = e^x
y'' = e^x
y''' = e^x
it's the special case in calculus... oo yeah.. i forget the c
2006-12-19 18:24:20
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answer #10
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answered by Mr.Math 1
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