Challenge Math Problem with Pool Area!! Must help!?

Question

Mr.Bricker gets a phone call from his good friend P-Diddy, who wants to build a pool inside his new mansion in Beverely Hills. He wants to build the pool inside. P'Diddy's pool is going to be L-shaped, with a walkway around the outer edge of the pool. To keep things safe for his kids, he also wants to build a fence around the pool. All dimensions will be measured in meters. The walkway will be te same width around the entire perimeter of the pool. The pool's shorter width is equal to 4 times the number of sides of a hexagon, divided by 3. The pool's longer width is 150% greater than the shorter width. The longest length of the pool is equal to the square of the number of teams remaining in te semifinals of any sports tounrmanet. The shorter length of the pool is equal to half a dozen. The pool with its walkway must fit perfectly in a space in the room measuring 552 sq. meters. 1) Help mr.bricker and his good friends find the width of the walway.
2. figure out how much fence is needed

Answer 1

You should be able to get all the lengths specified: for example, the number of sides in a hexagon is 6, and so the short width is 4*6/3 = 8. The only issue is the interpretation of 150%; this should be the same as 2.5x (not 1.5x: 1.5x is a 50% increase). So the longer width is 8*2.5 = 20. The shorter length is a half-dozen = 6, and the longer length is the the square of the number of teams in a semifinal = 4^2 = 16. Once you have all the pool dimensions you can compute the total area taken up by the pool (it is the sum of the areas of two rectangles). Subtract this from the total area of the space available (552 sq m) That must be the area of the walkway. The area of the walkway is the sum of the areas of several rectangles each of which has one side equal to W (the width of the walkway). Draw the picture of the pool, with the walkway surrounding it, break the walkway into smaller rectangles for which you know (or can figure) the long dimension (some of these will contain W also). Add all of these areas together and equate that to the area difference you found above. Solve for W (it will be a quadratic equation).

Answer 2

this may be a ratio undertaking: 2,500 / 50,000 = x / a million the place x is the needed volume of Algaecide it relatively is to be extra on your pool. 2,500 / 50,000 = x x = .05 = a million/20 of a gallon = 128 / 20 oz = 6.4 liquid oz. i wish that my changing from gallons to liquid ounceswill help you.