what is the percent yield if 45 grams of quicklime are obtained from 1 mole of calcium hydroxide?

Question

a company that produces quicklime,CaO, by heating calcium hydroxide, Ca(OH)2

(Ca molar mass=40.08g/mol

the answer is 80%
how would you solve this problem?

Answer 1

Ca(OH)2 --> CaO + H2O

Mr of Ca(OH)2 = 74
Mr of CaO = 56

% form = 56/75
= 75.6%
= 80% (round to 2 sf)