A begins with number 1; you return to A with number 9 and again with number 17 - it takes always takes 8 steps to come back to A. So divide 56789 by 8; you get 7098 remainder 5. This means you have gone from A completely back to A 7098 times and are now on step 5, which is E.
2006-12-19 17:06:05
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answer #1
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answered by wild_turkey_willie 5
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The product, E * 4, is continually even for any cost of E. hence, A should be a good digit, both 2, 4, 6 or 8. The product, A * 4 + carry = E, signifies that A can basically be a million or 2. yet A should be even, as shown. hence, A = 2. With A = 2, A * 4 + carry = 8 + carry, so E = 8 or 9. yet E * 4 = tens digit + A = tens digit + 2, so E is both 3 or 8, because basically 3 * 4 and eight * 4 bring about a 2. From both the superb statements, E should be 8.
2016-11-30 23:54:37
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answer #2
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answered by ? 4
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LOOK CAREFULLY FOLLOWING SEIRIES
ABCDEDCBABCDEDCB ABCDEDCBABCDEDCBA......
here this series can be divided in two parts:
each of 8 lettters whiah is repeating
A B C D E D C B |||| A B C D E D C B
1 2 3 4 5 6 7 8 |||| 9 10 11 12 13 14 15 16
SO which ever no comes divide it by 8 if reminder comes 0
then word "B" IS ANSWER
SO as per your question for
56789
divide it by 8
we get ans as 7098 most important the REMINDER is 5
so for 5 we have letter "E"
ANSWER : "E"
2006-12-19 19:04:30
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answer #3
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answered by cham 2
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A,B,C,D, and E represents 1,2,3,4,and 5 respectively
let Y = No. of steps
Let X = No. of variants (mean number of difference when u return to E)
In this case the no. of variants is 8, therefore;
Steps=No. of Steps/No. of Variants x 56789
steps= Y/8 x 56789
= 7098.625 steps
If I supposed to precisely steps up to 7096 steps at 8 in order to return to E, therefore 56768 is also belong to E which is less than 3 steps from what u give, therefore 56789 (the number you are trying to find out) is actually an E integer., do u believe that. . .
2006-12-19 18:52:22
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answer #4
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answered by nurrasid 1
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Edcba if u simply substitute letters for corresponding digits.
however the sequence for each digit is like for A =1+8n where n is the number each time u return back to it
so is true for B =2+6n, =3+4n, D = 4+2n, E =5+8n
so check for each combination and finsd if n comes out to be whole number. for eg. for A: 56789 = 1+8n=>no
for B : 56789 = 2 +6n => no
for C and D also no, for E :yes n = 14196
hence E corresponds to the given nmber.
2006-12-19 16:49:28
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answer #5
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answered by anami 3
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this number..56789 can be formed as groups of numbers....e.g.:56-78-9...try doing this...i'm sorry i don't have any other suggestions
2006-12-19 16:53:38
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answer #6
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answered by anty93 2
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edcba ......... substitute the numbers with the corresponding alphabet
2006-12-19 16:47:38
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answer #7
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answered by Srinivas c 2
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edcba for sure
2006-12-19 16:52:58
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answer #8
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answered by dragon 2
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