physics multiple choice?

Question

A 500-kilogram sports car accelerates uni-
formly from rest, reaching a speed of 30 me-
ters per second in 6 seconds.
During the 6 seconds, the car has traveled
a distance of

(a) 30 m
(b) 15 m
(c) 90 m
(d) 180 m
(e) 60 m

Answer 1

c) 90m
The average speed is 15 m/s times the time 6s = 90 meters.
Eds

Answer 2

Do you have the equations for motion with constant acceleration?

I'm sure someone here has probably already cranked out the math for you, but if you are in physics, these are very basic.

There are 3 or 4 equations using distance, velocity, acceleration, and time.

The equation you need for this one is
x=x init + 1/2( Vinit + Vx) * t

since x init and Vinit are zero from the problem statement, this becomes quite simple to solve.

If you are given 2 or 3 of the variables, distance, velocity, acceleration, or time, all you have to do is choose the equation with one unknown. Occasionally, you may be given some where you have to solve 2 sets of equations with 2 unknowns but if you are struggling with this one, you will really have a hard time with those.

Good luck

Answer 3

distance = 1/2 acceleration X ( time to the second power)
d=1/2 at^2
acceleration = change in velocity / change in time
a=(30-0)/(6-0) =5 m/s/s

distance = .5 X 5 X6^2=90 m

Answer 4

that is difficult looking rather questions from previous exams. Barron's and those 0.33 social gathering learn substances provide a very similar difficulty aspect as is on the AP try. yet earlier going out and paying for such stuff, communicate inclusive of your Physics instructor. He/she is sure to have cloth that you'll artwork on.

Answer 5

(c) 90

Acceleration = a = 30m/s / 6s = 5 m/s^2

x(t) = 0.5*a*t^2
x(t) = 0.5*5*6^2=90m

Answer 6

c

Answer 7

c

Answer 8

(c) 90m